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3 years ago

5. Do you think oppositional or symbiotic relationships are more beneficial to an ecosystem? Justify

Chemistry

1 answer:

mars1129 [50]3 years ago

6 0

Answer:

I think they are beneficial for the life of those symbiotic organisms that require yes or yes from another to be able to live.

Although an ecosystem could not be carried out if only this relationship would occur, since symbiotic relationships we have an organism where it needs another to live and even removes the necessary nutrients for it, that is why the chain should continue with other types of relationships .

Explanation:

The symbiosis is defined as "Intimate association of organisms of different species to mutually benefit in their vital development" that is why adequate coexistence between these living organisms is needed, otherwise this phenomenon would not occur.

A very good example of the symbiosis is: Bees and plants where the bee is the pollinating agent of the plant so that it continues to reproduce and the plant is the bee's food source.

Therefore I believe that the development of this type of relationship is VITAL, and very fundamental, otherwise I do not know if an ecosystem or a balanced ecosystem could be carried out.

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You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL

pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

3 0

3 years ago

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con

erik [133]

Explanation:

The given data is as follows.

Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K

Surface area (A) = 5 $m^{2}$ , $T_{1} = 14^{o}C$

$T_{2} = 93^{o}C$

According to Fourier's law,

Q = $-kA \frac{dT}{dx}$

Hence, putting the given values into the above formula as follows.

Q = $-kA \frac{dT}{dx}$

= $-13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}$

= 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

4 0

3 years ago

Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and

tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of $PCl_5$ is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

We are given:

$K_c=0.042$

$[PCl_3]=0.18M$

$[Cl_2]=0.30M$

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

$0.042=\frac{0.18\times 0.30}{[PCl_5]}$

$[PCl_5]=1.285$

Hence, the equilibrium concentration of $PCl_5$ is 1.285 M.

6 0

3 years ago

What is meant when one says that acetic acid is a stronger acid than benzoic acid?

kozerog [31]

Its the other way around actually. Benzoic acid is stronger than acetic acid because the electron-donating inductive effect (+I) by the alkyl group on acetic acid destabilise the conjugate base of acetic acid.

hope this helps :)

6 0

3 years ago

AJUTOR VA ROG AM TEST SI MAI AM 10 MINUTE AM NEVOIE DE SUBPUNCTUL C SI D

BabaBlast [244]

Explanation:

desk I have a lot of work and I will send it in the one

7 0

3 years ago