Answer:
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Answer:
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Explanation:
Mass of sulfuric acid = 0.98 g
Moles of sulfuric acid = 
Mass of sodium hydroxide = 0.240 g
Moles of sodium hydroxide = 

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :
of sulfuric acid
As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.
So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.
According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :
of sodium sulfate
Mass of 0.0030 moles of sodium sulfate :
0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Answer: This is because their valence electrons are located in the S - orbital
Explanation:
This is because their valence electrons are located in the S - orbital.
You'll want to add three amounts of heat.
(1) Specific heat of lowering the temperature from -135°C to the melting point -114°C
(2) Latent heat of fusion/melting
(3) Specific heat of elevating the temperature from -114°C to -50°C
(1) E = mCΔT = (25 g)(0.97 J/g·°C)(1 kJ/1000 J)(-114 - -135) = 0.509 kJ
(2) E = mΔH = (25 g)(5.02 kJ/mol)(1 mol/46.07 g ethanol) = 2.724 kJ
(3) E = mCΔT = (25 g)(2.3 J/g·°C)(1 kJ/1000 J)(-50 - -114) = 3.68 kJ
<em>Summing up all energies, the answer is 6.913 kJ.</em>
Answer: 600 kJ
-
Explanation:
C₃H₈ (g) + 5 O₂ (g) =============== 3 CO₂ (g) + 4 H₂O (l)
Δ⁰Hf kJ/mol -104 0 -393.5 -285.8
Δ⁰Hcomb C₃H₈ = 3(-393.5) + 4 (-285.80) - (-104) kJ/mol
Δ⁰Hcomb = 2219.70 kJ/mol
n= m /MW MW c₃H₈ = 44.1 g/mol
n= 12 g/44.1 g/mol = 0.27 mol
then for 12 g the heat released will be
0.27 mol x 2219.70 kJ/mol = 600 KJ