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oksano4ka [1.4K]
3 years ago
11

According to newton’s first law of motion, it is true that an object moving at a constant speed in a straight path will continue

to do so until a net force acts upon it.
a. True
b. False
Physics
2 answers:
sergiy2304 [10]3 years ago
6 0
In Newton's First Law of Motion, it is stated : 
"an object in motion will stay in motion and in the same direction until acted upon by an opposing force."
It is also applied to objects NOT in motion :
"An object at rest will stay at rest until acted upon by an unbalanced force."
Your question asks if "According to newton's first law of motion, it is true that an object moving at a constant speed in a straight path will continue to do so until a net force acts upon it. True or false?"
This is true.
I hope this helps!
Anastasy [175]3 years ago
5 0
The answer is A. True
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An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv
konstantin123 [22]

Answer:

8.91 %

Explanation:

Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

[Δg/g × 100 %]² = 79.4644 %²

taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0
3 years ago
A ground-fault circuit interrupter shuts down a circuit if it?
alukav5142 [94]
C: if it senses unequal currents
6 0
2 years ago
I did questions 2 and 3 but I don't know if they are right. Someone help!
Tems11 [23]

You got it right my friend

8 0
3 years ago
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HURRY PEASE what happens to current when there is a diode on the circuit and why?
kolbaska11 [484]

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

Explanation:

6 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!
Elan Coil [88]

The spring constant is 181.0 N/m

Explanation:

We can solve the problem by applying the law of conservation of energy. In fact, the elastic potential energy initially stored in the compressed spring is completely converted into gravitational potential energy of the dart when the dart is at its maximum height. Therefore, we can write:

\frac{1}{2}kx^2 = mgh

where the term on the left represents the elastic potential energy of the spring while the term on the right is the gravitational potential energy of the dart at maximum height, and where

k is the spring constant of the spring

x = 2.08 cm = 0.0208 m is the compression of the spring

m = 12.3 g = 0.00123 kg is the mass of the dart

g=9.8 m/s^2 is the acceleration due to gravity

h = 3.25 m is the maximum height of the dart

Solving for k, we find:

k=\frac{2mgh}{x^2}=\frac{2(0.00123)(9.8)(3.25)}{(0.0208)^2}=181.0 N/m

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
3 years ago
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