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oksano4ka [1.4K]
3 years ago
11

According to newton’s first law of motion, it is true that an object moving at a constant speed in a straight path will continue

to do so until a net force acts upon it.
a. True
b. False
Physics
2 answers:
sergiy2304 [10]3 years ago
6 0
In Newton's First Law of Motion, it is stated : 
"an object in motion will stay in motion and in the same direction until acted upon by an opposing force."
It is also applied to objects NOT in motion :
"An object at rest will stay at rest until acted upon by an unbalanced force."
Your question asks if "According to newton's first law of motion, it is true that an object moving at a constant speed in a straight path will continue to do so until a net force acts upon it. True or false?"
This is true.
I hope this helps!
Anastasy [175]3 years ago
5 0
The answer is A. True
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Answer:

yes

Explanation:

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5 0
2 years ago
A rabbit is hopping along at an approximately constant speed of 3.9 m/s. The rabbit passes a crouched cat ready to chase the rab
Firlakuza [10]

Answer:

t  = 7,8 s

Explanation:

From the instant, the rabbit passes the cat. The cat star running acceleration of 0,5 m/s² .

When the cat arrives at the speed of 3,9 m/s the cat catches the rabbit

Then for the cat arrives at 3,9 m/s nedds

v = vo + a*t     vo  = 0  then   v = a*t

3,9 ( m/s) = 0,5 ( m/s² ) * t

t  = 7,8 s

v  =  3,9 m/s =

4 0
2 years ago
An object of mass 300 g, moving with an initial velocity of 5.00i-3.20j m/s, collides with an sticks to an object of mass 400 g,
Alexus [3.1K]

Answer:

Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

Explanation:

Mass of object 1 , m₁ = 300 g = 0.3 kg

Mass of object 2 , m₂ = 400 g = 0.4 kg

Initial velocity of object 1 , v₁ = 5.00i-3.20j m/s

Initial velocity of object 2 , v₂ = 3.00j m/s

Mass of composite = 0.7 kg

We need to find final velocity of composite.

Here momentum is conserved.

Initial momentum = Final momentum

Initial momentum = 0.3 x (5.00i-3.20j) + 0.4 x 3.00j = 1.5 i + 0.24 j kgm/s

Final momentum = 0.7 x v = 0.7v kgm/s

Comparing

1.5 i + 0.24 j = 0.7v

v = 2.14 i + 0.34 j

Magnitude of velocity      

       v=\sqrt{2.14^2+0.34^2}=2.17m/s

Direction,  

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Velocity is 2.17 m/s at an angle of 9.03° above X-axis.

7 0
3 years ago
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soldi70 [24.7K]

Answer:

The angle that the wave would be \theta = sin ^{-1}\frac{2 \lambda}{D}

Explanation:

From the question we are told that  the  opening to  the  harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the  on at angle greater than the diffraction first minimum would be slightly affected

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Since for second minimum m= 2

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