When hydrogen burns, water vapor is produced. the equation is 2h2(g) + o2(g) → 2h2o(g). if 12 l of oxygen are consumed at stp, w
hat volume of water vapor is produced?
1 answer:
The volume of water vapor produced if 12 l of oxygen are consumed at STP is calculated as follows
2H2(g) +O2 (g) = 2H2O
by use of mole ratio between O2 to H2O which is 1:2 the number of liters of H2O produced is therefore
= 2/1 x12 L = 24 L
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