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Inga [223]
3 years ago
13

When hydrogen burns, water vapor is produced. the equation is 2h2(g) + o2(g) → 2h2o(g). if 12 l of oxygen are consumed at stp, w

hat volume of water vapor is produced?
Chemistry
1 answer:
loris [4]3 years ago
5 0
The  volume  of water  vapor  produced if  12 l  of  oxygen  are consumed at STP  is calculated as follows

2H2(g)  +O2 (g)  = 2H2O

by use  of mole ratio  between   O2 to H2O  which  is  1:2  the  number of liters  of H2O produced  is therefore

=  2/1 x12  L =  24 L
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Fe(NO3)2 not sure how to get the oxidation numbers of all elements
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You must remember that oxidation number of hydrogen in acids is always +1, oxidation number of oxygen in oxides & acids is always -2... metals has always oxidation number on plus!

group NO3 comes from HNO3...and oxidation number of whole acid group is always on minus and equal to the amount of hydrogen atoms in this acid... so oxidation number of NO3 = -1

we have 2 NO3 groups so 2*(-1) = -2 and that is the reason why oxidation number of Fe in this formula must be +2... because sum of all elements always gives 0!

Now we could count of oxidation number for nitrogen... we write HNO3 and start counting from right to left:
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2 years ago
Write the chemical equation for the reaction that occurs when 6 m hcl solution is added to the reaction mixture.
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When u add the solution to the chemical's
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3 years ago
A mixture of H2 and water vapor is present in a closed vessel at 20. 00°C. The total pressure of the system is 755. 0 mmHg. The
MAVERICK [17]

The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

  • P.V=n.R.T
  • We must convert mmHg to atm. 760 mmHg.
  • 1 atm
  • 755 mmHg (755/760) = 0.993 atm
  • 0.993 m.1L=n.0.082 L.atm/mol.K .
  • 293 K(0.993 atm 1.1L)/(0.082mol.K /L.atm).
  • 293K = n
  • 0.0413mols = n

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

  1. P.V=n.R.T
  2. 760 mmHg. 1 atm
  3. 17.5 mmHg (17.5 mmHg / 760 mmHg)=0.0230 atm
  4. 0.0230 m.1L=n.0.082 L.atm/mol.K.293 K(0.0230atm.1L)/(0.082mol.K/L.atm .293K)=n 9.58 × 10 ^ 4 mols = n.
  5. Molar fraction = mols )f gas/general mols.
  6. Molar fraction water vapor =9.58×10^ -four mols / 0.0413 mols
  7. Sum of molar fraction =1
  8. 1 - 9.58 × 10 ^ 4 × mols / 0.0413 ×mols = molar fraction H2
  9. 0.9767 = molar fraction H2
  10. H2 pressure / Total pressure =molar fraction H2
  11. H2 pressure / 55mmHg = =0.9767 0.9767 = h2 pressure =755 mmHg.
  12. 737,47 mmHg.
<h3>What is a mole fraction?</h3>

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

To learn  more about partial pressure refer to the link :

brainly.com/question/19813237

<h3 />

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The most appropriate SI unit used to measure the length of a book would be Centimeters.

The most appropriate SI unit to use for the volume of a book is centimeters cubed

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