When hydrogen burns, water vapor is produced. the equation is 2h2(g) + o2(g) → 2h2o(g). if 12 l of oxygen are consumed at stp, w
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Answer:
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Explanation:
Moles of hydrochloric acid = n
Volume of hydrochloric acid solution = 200.0 mL = 0.200 L
Molarity of the hydrochloric acid = 0.089 M
of HCL
According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.
Then 0.0178 moles of HCl wil be neutralized by :
of sodium bicarbonate
Mass of 0.0178 moles of sodium bicarbonate:
0.0178 mol × 72 g/mol = 1.4952 g
1.4952 grams of sodium bicarbonate she would need to ingest to neutralize this much HCl.
Answer: 2.796 grams
Explanation:
According to stoichiometry:
1 mole of reacts with 1 mole of
0.012 moles of will react with=
of
Thus is the limiting reagent as it limits the formation of product.
is the excess reagent as (0.018-0.012)=0.006 moles are left unused.
1 mole of produces 1 mole of
0.012 moles of will produce=
of
Mass of
Thus 2.796 grams of are produced.