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Over [174]
3 years ago
13

Which element has four energy levels? Na,K,Cs,Rb

Chemistry
2 answers:
Ann [662]3 years ago
7 0
Potassium K 

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Alik [6]3 years ago
6 0

Answer:

The correct option is: Potassium

Explanation:

Sodium, Potassium, Rubidium and Caesium are referred to as the alkali metals that belong to the group 1 of the periodic table, thus having one valence electron in their outer or valence shell.

Sodium, atomic number 11, belongs to the period 3 of the periodic table. It has <u>three shells</u> and the number of electrons per shell is 2, 8, 1.

Potassium, atomic number 19, belongs to the period 4 of the periodic table. It has <u>four shells</u> and the number of electrons per shell is 2, 8, 8, 1.

Rubidium, atomic number 37, belongs to the period 5 of the periodic table. It has <u>five shells</u> and the number of electrons per shell is 2, 8, 18, 8, 1.

Caesium, atomic number 37, belongs to the period 6 of the periodic table. It has <u>six shells</u> and the number of electrons per shell is 2, 8, 18, 18, 8, 1.

<u>Therefore, </u><u>Potassium</u><u>, atomic number 19, has four shells or energy levels.</u>

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D. Surface tension.

Explanation:

Surface tension is defined as the energy required to increase the surface area of a liquid by a unit amount.

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What is hydrogenation​
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Hydrogenation – meaning, to treat with hydrogen – is a chemical reaction between molecular hydrogen and another compound or element, usually in the presence of a catalyst such as nickel, palladium or platinum. The process is commonly employed to reduce or saturate organic compounds

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Which of the following is NOT a characteristic of a strong acid?
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a and c

Explanation:

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3 years ago
2. Sitting on a bench top are several samples: lithium metal (d = 0.53 g/mL), gold (d = 19.3 g/mL), aluminum (d = 2.70 g/mL), an
Snezhnost [94]

Answer:

The sample of lithium occupies the largest volume.

Explanation:

Given the densities for the four elements, we have the expression d=\frac{m}{V} that shows the relationship between mass and Volume to express the density of an element.

For each element we have:

d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL

d_{gold}=\frac{m_{gold}}{V_{gold}}=19.3g/mL

d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL

d_{lead}=\frac{m_{lead}}{V_{lead}}=11.3g/mL

The problem says that all the samples have the same mass, so:

m_{lithium}=m_{gold}=m_{aluminum}=m_{lead}=m

it means that m is a constant

Now, solving for the Volume in each element and with m as a constant, we have:

V_{lithium}=\frac{m}{d_{lithium}}

V_{lithium}=\frac{1}{0.53\frac{g}{mL}} *m

V_{lithium}=1.88\frac{mL}{g}*m

V_{gold}=\frac{m}{d_{gold}}

V_{gold}=\frac{1}{19.3\frac{g}{mL}} *m

V_{gold}=5.18*10^{-2}\frac{mL}{g}*m

V_{aluminum}=\frac{m}{d_{aluminum}}

V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m

V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m

V_{lead}=\frac{m}{d_{lead}}

V_{lead}=\frac{1}{11.3\frac{g}{mL}} *m

V_{lead}=8.85*10^{-2}\frac{mL}{g}*m

If we assume m = 1g, we find that:

V_{lithium}=1.88mL

V_{gold}=5.18*10^{-2}mL

V_{aluminum}=3.70*10^{-1}mL

V_{lead}=8.85*10^{-2}mL

So we can see that the sample of lithium occupies the largest volume with 1.88mL

Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.

4 0
2 years ago
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