Mercury (Hg) is present in trace amounts in coal, ranging from 50.0 to 200.0 ppb. A typical power plant burns 2.39 million tons
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Answer: 1 mol of will be produced from this reaction.
Explanation: Reaction follows,
As seen from the balanced chemical equation above, we get
For every 3 moles of Aluminium and 3 moles of , 1 mole of
is formed.
For every 3 moles of Aluminium and 3 moles of , 1 mole of
is formed.
For every 3 moles of Aluminium and 3 moles of , 3 moles of
is formed.
For every 3 moles of Aluminium and 3 moles of , 6 moles of
is formed.
Answer:
Theoretical yield = 3.51 g
Explanation:
The formula for the calculation of moles is shown below:
For :-
Mass of = 1.28 g
Molar mass of = 16.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
For :-
Mass of = 10.1 g
Molar mass of = 31.998 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:
1 mole of methane gas reacts with 2 moles of oxygen gas
0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas
Moles of oxygen gas = 0.1596 moles
Available moles of oxygen gas = 0.3156 moles
<u>Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.
</u>
The formation of the product is governed by the limiting reagent. So,
1 mole of methane gas on reaction produces 1 mole of carbon dioxide.
0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.
Mole of carbon dioxide = 0.0798 mole
Molar mass of carbon dioxide = 44.01 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of = 3.51 g
<u> Theoretical yield = 3.51 g</u>