Ask question

Ask question

All categories

4 years ago

10

List at least 3 physical properties that the professor describes of his newly discovered flubber

2 answers:

natka813 [3]4 years ago

8 0

Answer:

Flubber is a combination of two words Fluid+ Rubber. It means flubber has physical properties of both fluid and rubber(solid).

Physical properties of Flubber are as follows

1. It has elasticity like rubber

2. It can take the shape of the container in which it is filled. It does not have any particular shape like fluid.

3.It has viscoplastic nature

4. It is gelatinous

5. It flows under low pressure and can break when high pressure is applied on it.

mestny [16]4 years ago

6 0

Whales
Quails
Trails Its a physical property

You might be interested in

What is the rate of flow of electric charge around a circuit

oksian1 [2.3K]

Electric Current: The rate of flow of charge is current. An ampere is the flow of one coulomb through an area in one second.

5 0

3 years ago

Read 2 more answers

What is true about all uranium atoms

tamaranim1 [39]

Answer:

erm they all should have same numbers of protons

3 0

3 years ago

Read 2 more answers

A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc

Artist 52 [7]

Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

The distance traveled by car after Δt (seconds) at $v_c = 23m/s$ speed is

$s_c = \Delta t v_c = 23\Delta t$

The distance traveled by the motorcycle after Δt (seconds) at $m_m = 23 m/s$ speed and acceleration of a = 8 m/s2 is

$s_m = \Delta t v_m + a\Delta t^2/2$

$s_m = 23\Delta t + 8\Delta t^2/2 = 23 \Delta t + 4 \Delta t^2$

We know that the motorcycle catches up to the car after Δt, so it must have covered the distance that the car travels, plus their initial distance:

$s_m = s_c + 58$

$23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58$

$4 \Delta t^2 = 58$

$\Delta t^2 = 14.5$

$\Delta t = \sqrt{14.5} = 3.807s$

(b)

$s_m = 23 \Delta t + 4 \Delta t^2$

$s_m = 23*3.807 + 58 = 145.581 m$

5 0

3 years ago

It takes 50 seconds for Tyler to do 450 Joules of work. How much power did Tyler use?

Tomtit [17]

Answer:

<h2>The answer is 9 W</h2>

Explanation:

The power used by an object can be found by using the formula

$p = \frac{w}{t} \\$

w is the workdone

t is time taken

From the question we have

$p = \frac{450}{50} = \frac{45}{5} \\$

We have the final answer as

<h3>9 W</h3>

Hope this helps you

8 0

3 years ago

Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance

scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

$x_{1}=\dfrac{\lambda D}{2d}$

Second minima from center

$x_{2}=\dfrac{3\lambda D}{2d}$

The distance between the places where the intensity is zero due to the double slit effect

$\Delta x_{d}=x_{2}-x_{1}$

$\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}$

$\Delta x_{d}=\dfrac{\lambda D}{d}$

Put the value into the formula

$\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}$

$\Delta x_{d}=0.015 =15\times10^{-3}\ m$

$\Delta x_{d}=15\ mm$

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0

3 years ago