1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
3 years ago
6

It was a cold, sunny day and the ground was covered with fresh snow. Maria wore her black sweatshirt outside to play in the snow

. She knew that black would _________ light waves and help keep her warm.
refract


absorb


diffract


reflect
Physics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer: The correct answer is absorb.

Explanation:

In the given problem, It was a cold, sunny day and the ground was covered with fresh snow. Maria wore her black sweatshirt outside to play in the snow.

A black color is a good absorber while the white color is good reflector.

Black objects absorb all the incident radiations which falls on them regardless of the frequencies of the radiations while the white reflects all the incidents radiations completely.

Therefore, she knew that black would absorb light waves and help keep her warm.

Sonbull [250]3 years ago
5 0

It was a cold, sunny day and the ground was covered with fresh snow. Maria wore her black sweatshirt outside to play in the snow. She knew that black would absorb light waves and help keep her warm

You might be interested in
How do lines of latitude affect how direct or indirect the Sun’s rays are on the Earth?
IgorLugansk [536]
The technical definition of latitude is the angular distance north or south from the earth's equator measured through 90 degrees. ... Locations at lower latitudes receive stronger and more direct sunlight than locations near the poles. Energy input from the sun is the main driving force in the atmosphere.



The Seasons at Different Latitudes
The seasonal effects are different at different latitudes on Earth. Near the equator, for instance, all seasons are much the same. Every day of the year, the Sun is up half the time, so there are approximately 12 hours of sunshine and 12 hours of night.



When we consider Latitude alone as a control, we know that the low latitudes (say from the Equator to approximately 30 degrees N/S) are the warmest across the year (on an annual basis).
8 0
3 years ago
A power boat pulls a water skier 2.6 km maintaining a
Luba_88 [7]

Answer:

W = 650 [kJ]

Explanation:

The definition of work is denoted by the product of force by the distance traveled by the body, this distance traveled corresponds to the direction of the force.

In this case we have:

d = distance = 2.6[km] = 2600 [m]

F = force = 250 [N]

W = F*d = 250 * 2600 = 650000 [J] or 650 [kJ]

7 0
3 years ago
Two polarizing sheets have their transmission axes crossed so that no light is transmitted. A third sheet is inserted so that it
jek_recluse [69]

Answer:

a)    I= I₀ (cos²θ - cos⁴θ)    b) 75.5º

Explanation:

a) For this exercise we must use Malus's law

         I = I₀ cos² θ

where tea is the angle between the two polarizers.

We apply this expression to our case

* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical

         I₁ = I₀ cos² θ

* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.

The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical

              θ₂ = 90- θ’ = θ

fiate that in the exercise we must take a reference system and measure everything with respect to this system.

          I = I₁ cos² θ'

       

we substitute

         I = (I₀ cos² tea) cos² (θ - 90)

        cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ

         I = Io cos² θ sin² θ

        1= cos²θ+ sin²θ

       sin²θ = 1 - cos²θ

        I= I₀ (cos²θ - cos⁴θ)

b) to find when the intensity is maximum,

we can use that we have an extreme point when the drift is zero

          \frac{dI}{d \theta} = 0

          \frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0

whereby

            cos θ - 2 cos³ θ = 0

            cos θ ( 1 - 2 cos² θ) = 0  

The zeros of this function are in

           θ = 90º

           1-2cos²θ =0       cos θ = 0.25  θ =  75.5º

Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.

Consequently, the angle that allows the maximum intensity to pass is 75.5º

5 0
3 years ago
List 3 quantities of waves.
VARVARA [1.3K]
If you mean like electromagnetic waves then, Mico waves, UV rays, and infrared waves
8 0
3 years ago
Read 2 more answers
If stellar parallax can be measured to a precision of about 0.01 arcsec using telescopes on the Earth to observe stars, to what
marin [14]

Answer:

It corresponds to a distance of 100 parsecs away from Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

It is defined in a analytic way as it follows:

       

\tan{p} = \frac{1AU}{d}

Where d is the distance to the star.

p('') = \frac{1}{d} (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')} (2)

Equation (2) represents the distance in a unit known as parsec (pc).

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth (as is shown in the image below), knowing that the distance between the Earth and the Sun (150000000 Km), is defined as 1 astronomical unit (1AU).

For the case of   (p('') = 0.01):

d(pc) = \frac{1}{0.01}

d(pc) = 100

Hence, it corresponds to a distance of 100 parsecs away from Earth.

<em>Summary:</em>

Notice how a small parallax angle means that the object is farther away.

Key terms:

Parsec: Parallax of arc second

7 0
3 years ago
Other questions:
  • A jogger travels 8.0 km in 1.25 hours.what is the jogger's average speed
    13·1 answer
  • Calculate how much an astronaut with mass of 90 kg would weigh while standing on the surface of Mars. The acceleration due to gr
    9·1 answer
  • The clouds that occur at the highest altitude are usually
    6·2 answers
  • A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
    12·1 answer
  • Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.
    13·2 answers
  • Which state of matter exist in an extreme high temperature found on stars
    11·2 answers
  • From the top of a tall building, you throw one ball straight up with speed v0 and one ball straight down with speed v0. (a) Whic
    8·1 answer
  • Hello:) how to do 3?:)
    7·1 answer
  • Why is Radiology important in the medical field?
    15·1 answer
  • - A straight wire, 0.20 m long, moves at a constant speed of 7.0 m/s
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!