Answer:
True
Explanation:
Magnitude is the "value" the greater the value the greater the force is and vice versa
Answer:
d A ball is rolling down an inclined plane.
Explanation:
When path length is equal to the displacement
then we can say that the motion of the object must be in straight line so that the distance and displacement must be same
SO here we can say
a A ball on the end of a string is moving in a vertical circle.
In circular path distance and displacement is not same
b A toy train is traveling around a circular track.
In circular path distance and displacement is not same
c A train travels 5 miles east before it stops. It then travels 2 miles west.
Net displacement is 3 miles East while distance is 7 miles
d A ball is rolling down an inclined plane.
Here its motion is in straight line so we can say that path length and displacement will be same
e A ball rises and falls after being thrown straight up from the earth's surface.
In this type of to and fro motion path length is not same as displacement
Answer:
The induced emf in the coil is 0.522 volts.
Explanation:
Given that,
Radius of the circular loop, r = 9.65 cm
It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.
The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , ![\dfrac{dr}{dt}=-0.756\ m/s](https://tex.z-dn.net/?f=%5Cdfrac%7Bdr%7D%7Bdt%7D%3D-0.756%5C%20m%2Fs)
Due to the shrinking of radius of the loop, an emf induced in it. It is given by :
![\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V](https://tex.z-dn.net/?f=%5Cepsilon%3D%5Cdfrac%7B-d%5Cphi%7D%7Bdt%7D%5C%5C%5C%5C%5Cepsilon%3D%5Cdfrac%7B-d%28BA%29%7D%7Bdt%7D%5C%5C%5C%5C%5Cepsilon%3DB%5Cdfrac%7B-d%28%5Cpi%20r%5E2%29%7D%7Bdt%7D%5C%5C%5C%5C%5Cepsilon%3D2%5Cpi%20rB%5Cdfrac%7Bdr%7D%7Bdt%7D%5C%5C%5C%5C%5Cepsilon%3D2%5Cpi%20%5Ctimes%209.65%5Ctimes%2010%5E%7B-2%7D%5Ctimes%201.14%5Ctimes%200.756%5C%5C%5C%5C%5Cepsilon%3D0.522%5C%20V)
So, the induced emf in the coil is 0.522 volts.
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Explanation:
current = velocity/resistance
I = V/R
15/4
current = 3.75A
hope this helps...