Answer:
Explanation:
given,
cyclist ride 6.2 km east and then 9.28 km in the direction of 27.27° west of north and then 7.99 km west.
vertical component = 9.28 cos∅
= 9.28 cos 27.27°
= 8.24 km
horizontal axis component = 9.28 sin ∅
= 9.28 sin 27.27°
= 4.5 km
distance of the final point from the origin
= 7.99 -(6.2-4.5)
= 6.29 km
displacement
![d = \sqrt{6.29^2+8.24^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B6.29%5E2%2B8.24%5E2%7D)
d = 10.37 km
b) ![tan \theta = \dfrac{6.29}{8.24}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cdfrac%7B6.29%7D%7B8.24%7D)
θ = 37.36°
Get your numbers gathered up and solve the problem in the ordered step
Answer:
The index of refraction of the liquid is n = 1.33 equivalent to that of water
Explanation:
Solution:-
- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.
- The index of refraction is material property and proportional to density of the material.
- The denser the material the slower the light will move through associated with considerable diffraction angles.
- The lighter the material the faster the light pass through the material without being diffracted as much.
- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.
- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.
- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.
- The light passes through a liquid with speed v = 2.25*10^8 m/s :
![n = c / v\\\\n = \frac{ 3*10^8 }{2.25*10^8} \\\\n = 1.33](https://tex.z-dn.net/?f=n%20%3D%20c%20%2F%20v%5C%5C%5C%5Cn%20%3D%20%5Cfrac%7B%203%2A10%5E8%20%7D%7B2.25%2A10%5E8%7D%20%5C%5C%5C%5Cn%20%3D%201.33)
- The index of refraction of the liquid is n = 1.33 equivalent to that of water.