... the angular tilt of the Earth's position on its axis relative to the sun
1250 decigrams
1 gram = 10 decigrams
Answer:
the time interval that an earth observer measures is 4 seconds
Explanation:
Given the data in the question;
speed of the spacecraft as it moves past the is 0.6 times the speed of light
we know that speed of light c = 3 × 10⁸ m/s
so speed of spacecraft v = 0.6 × c = 0.6c
time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds
Now, from time dilation;
t = Δt₀ / √( 1 - ( v² / c² ) )
t = Δt₀ / √( 1 - ( v/c )² )
we substitute
t = 3.2 / √( 1 - ( 0.6c / c )² )
t = 3.2 / √( 1 - ( 0.6 )² )
t = 3.2 / √( 1 - 0.36 )
t = 3.2 / √0.64
t = 3.2 / 0.8
t = 4 seconds
Therefore, the time interval that an earth observer measures is 4 seconds
Answer:
141.152 miles per hour is the speed of the plane in miles per hour
Explanation:
Speed of plane = Total distance travelled/total time taken -
v = D/t
Substituting the given values in the above equation, we get
v = 467/3.3 miles /hour
v = 141.152 miles per hour
141.152 miles per hour is the speed of the plane in miles per hour
