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Andrej [43]
3 years ago
15

Algorithm to determine number of shortest paths between two nodes

Physics
1 answer:
Lunna [17]3 years ago
5 0
Search Results<span>Use BFS to determine the length of the shortest v-w-path. Then use DFS to find thenumber of the v-w-shortest paths such that two nodes are connected and the length of path equals to the output of BFS. But the running time of this plan is O(m+n)+O(m+n). Also I've tried to modify the Dijkstra algorithm.</span>
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a cepheid variable star is a star whose brightness alternately increases and decreases. suppose that cephei joe is a star for wh
MrRissso [65]

After one day, the rate of increase in Delta Cephei's brightness is;0.46

We are informed that the function has been used to model the brightness of the star known as Delta Cephei at time t, where t is expressed in days;

B(t)=4.0+3.5 sin(2πt/5.4)

Simply said, in order to determine the rate of increase, we must determine the derivative of the function that provides

B'(t)=(2π/5.4)×0.35 cos(2πt/5.4)

Currently, at t = 1, we have;

B'(1)=(2π/5.4)×0.35 cos(2π*1/5.4)

Now that the angle in the bracket is expressed in radians, we can use a radians calculator to determine its cosine, giving us the following results:

B'(1)=(2π/5.4)×0.3961

B'(1)≈0.46

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Describe and explain the potential energy changes that occur during the formation of a covalent bond
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Suppose you push a toy train with a force of 3 N east. The train has a mass of 0.5 kg. What is its acceleration?
Sergeu [11.5K]
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4 years ago
Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

\lambda=\frac{b}{T}

where

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T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot K is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

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