Answer:
The velocity of the gun relative to the ground is 19.66 m/s
Explanation:
Given data,
The mass of the gun, M = 15.0 kg
The mass of the bullet, m = 50 g
The velocity of the train, v = 75 km/h
= 20.83 m/s
The velocity of bullet relative to train, V' = 350 m/s
The velocity of bullet relative to ground, V = 350 + 20
= 370 m/s
According to the law of conservation of momentum,
Mv' + mV' = 0


= -1.17 m/s
Therefore, the velocity of the gun with,
v₀ = V + v'
= 20.83 - 1.17
= 19.66 m/s
Hence, the velocity of the gun relative to the ground is 19.66 m/s
<h3>
Answer:</h3>
800 meters
<h3>
Explanation;</h3>
<u>We are given;</u>
- Speed as 40 m/s
- Time as 20 seconds
We are required to determine the distance traveled
- Speed refers to the rate of change in distance.
- It is given by;
Speed = Distance ÷ time
Rearranging the formula;
Distance = speed × time
In this case;
Distance = 40 m/s × 20 sec
= 800 meters
Thus, the distance traveled by the car is 800 m
Is there any chemical names listed ?
Answer:
3 seconds
Explanation:
Applying,
Applying,
v = u±gt................ Equation 1
Where v = final velocity, u = initial velocity, t = time, g = acceleration due to gravity.
From the question,
Given: v = 0 m/s ( at the maximum height), u = 30 m/s
Constant: g = -10 m/s
Substitute these values into equation 1
0 = 30-10t
10t = 30
t = 30/10
t = 3 seconds