Answer:
Solution A: 3.21% (m/v) NaCl ⇒ CRENATION
Solution B: 1.65% (m/v) glucose ⇒ HEMOLYSIS
Solution C: distilled H₂O ⇒ HEMOLYSIS
Solution D: 6.97% (m/v) glucose ⇒ CRENATION
Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl ⇒ CRENATION
Explanation:
Isotonic solution = 0.9% (m/v) NaCl or 5.0% (m/v) glucose
<u>Crenation</u> will occur if the solution has a concentration higher than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypertonic solution). This will occur in the following solutions:
Solution A: 3.21% (m/v) NaCl > 0.9% (m/v) NaCl
Solution D: 6.97% (m/v) glucose > 5.0% (m/v) glucose
Solution E: 5.0% (m/v) glucose <u>and</u> 0.9%(m/v) NaCl (the addition of the 2 components exceeds the osmotic pressure permitted).
<u>Hemolysis</u> will occur if the solution has a concentration lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose (hypotonic solution). This is the case of:
Solution B: 1.65% (m/v) glucose < 5.0% (m/v) glucose
Solution C: distilled H₂O = 0% glucose/0% NaCl < 0.9% (m/v) NaCl or 5.0% (m/v) glucose
The mass, in grams, of the sample of methanol (CH₃OH) is 64 grams.
<h3>How we calculate mass from moles?</h3>
Mass of any substance can be calculated by using moles as:
n = W/M, where
W = required mass
M = molar mass
In the question that:
Moles of methanol = 2mole
Molar mass of methanol = 32g/mole
On putting these values in the above equation, we get
W = n × M
W = 2mole × 32g/mole = 64g
Hence, 64 grams is the mass of the sample.
To know more about moles, visit the below link:
brainly.com/question/15374113
