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Mkey [24]
3 years ago
14

A 390 mL solutions of 4.6 M HCl is left out over the weekend and 74 mL of solvent evaporates. What is the new concentration of H

Cl?
Chemistry
1 answer:
storchak [24]3 years ago
8 0

Answer:

5.7 M

Explanation:

You have .390 L of 4.6 M HCl.

.390 L * 4.6 mol/L = 1.794 mol HCl

.390-.074=.316 L solvent remaining

1.794 mol/.316 L=5.7 M HCl

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What is the mass number of an element with an atomic number 10 and 10 neutrons
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Explanation:

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(a) the temperature on a warm summer day is 87 °f. what is the temperature in °c? (b) many scientific data are reported at 25
olchik [2.2K]

Answers:

              (a)  30.55 °C

              (b) 298 K and 77°F

              (c)  204.44 °C and 477.44 K

              (d)  -320.8 °F and -196 °C

Explanation:

Converting °C into °F;

                                   °F  =  °C × 1.8 + 32

Converting °F into °C;

                                   °C  =  °F - 32 ÷ 1,8

Converting °C into K;

                                   K  =  °C + 273

Converting K into °C;

                                   °C  =  K - 273

8 0
3 years ago
How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
3 years ago
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