Answer:
The equilibrium concentration of NO is 0.02124 M.
Explanation:
Given that,
Initial concentration of NOBr = 0.878 M

Temperature = 24°C
We know that,
The balance equation is

Initial concentration is,

Concentration is,

Equilibrium concentration

We need to calculate the value of x
Using formula of concentration
![k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}](https://tex.z-dn.net/?f=k_%7Bc%7D%3D%5Cdfrac%7B%5BNO%5D%5BBr_%7B2%7D%5D%7D%7B%5BNOBr%5D%5E2%7D)
Put the value into the formula
![3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}](https://tex.z-dn.net/?f=3.07%5Ctimes10%5E%7B-4%7D%3D%5Cdfrac%7B%5B2x%5D%5Bx%5D%7D%7B%5B0.878-2x%5D%5E2%7D)





We need to calculate the equilibrium concentration of NO
Using formula of concentration of NO

Put the value of x


Hence, The equilibrium concentration of NO is 0.02124 M.
Answer:
It is also called a finite resource
Explanation:
<u>Given:</u>
Change in internal energy = ΔU = -5084.1 kJ
Change in enthalpy = ΔH = -5074.3 kJ
<u>To determine:</u>
The work done, W
<u>Explanation:</u>
Based on the first law of thermodynamics,
ΔH = ΔU + PΔV
the work done by a gas is given as:
W = -PΔV
Therefore:
ΔH = ΔU - W
W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ
Ans: Work done is -9.8 kJ
Answer:
the pig's average speed is 7 m/s