In a Washington town, the charge for commerical waste collection is $694.55 for 5 tons of waste and $1098.56 for 8 tons of waste
1 answer:
Answer:
And we can find the intercept like this:
And the equation would be given by:
Step-by-step explanation:
For this case we want a function given by:
Where C is the cost, m the slope, w the weight and b the intercept.
We have the following info (w=5, C= 694.55) and (w=8, C=1098.56) and we can find the slope with this formula:
And we can find the intercept like this:
And the equation would be given by:
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Answer:
- 25000 seats in section A
- 14100 seats in sectin B
- 10900 seats in section C
Step-by-step explanation:
The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is
... 25000×$25 = $625,000
so the revenue from B and C seats must total
... $1,070,500 - 625,000 = $445,500
If all 25000 of the B/C seats were C seats, the revenue would be
... 25000×$15 = $375,000
The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...
... $70,500/$5 = 14,100 . . . . B seats
Then the balance of the 25000 B and C seats are C seats:
... 25,000 - 14,100 = 10,900 . . . . C seats
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<em>Alternate Solution Method</em>
The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...
- a + b + c = 50000
- a - b - c = 0
- 25a + 20b + 15c = 1070500
so the augmented matrix is ...
A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.
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<em>Comment on the Working</em>
Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.
As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.
If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:
... 20b + 15(25000-b) = 445,500
... 5b = 445,500 - 375000 . . . . simplify, subtract 375000
... b = 70500/5 = 14100
Answer:
The solar panel produce 6.48 × 10⁶ J of energy each day.
Step-by-step explanation:
If the solar cells were 100% efficient and generate 1000 watts of power per square meter
The power generated per square meter will be
= 1000 watts/m²
This is the power that would be generated per square meter if the solar cells were 100% efficient.
Now, for a 1 square meter panel of solar cells with an efficiency of 30%, the power generated will be
= 300 watts
This is the power that would be generated by a 1 square meter panel of solar cells with an efficiency of 30%
Now, to determine the energy in joules (J) that the solar panel produce each day
We can determine the energy from the formula
Energy = Power × time
From the question, the solar cells receives the equivalent of 6 hours of direct sunlight per day, that is
Time = (6 × 60 × 60) secs = 21600 secs
Hence,
Energy = 300 watts × 21600 secs
Energy = 6480000 Joules
Energy = 6.48 × 10⁶ J