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2 years ago

13

A drum company advertises a snare drum that is 2 inches high and 12 inches in diameter. Find the volume

1 answer:

loris [4]2 years ago

8 0

Answer:904.78

Step-by-step explanation:

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Find the circumference.<br> Use 3.14 for it.<br> r = 5 cm<br> C = [?] cm<br> C= Ttd

azamat

Answer:

C=2(3.14)×(5)

C=31.4cm

3 0

2 years ago

PLEASE HELP!! NO LINKS!!

dlinn [17]

Answer:

42.1 cm

Step-by-step explanation:

θ = 265°

Radius (r) = 9.1 cm

Arc length of major arc GH = θ/360 × 2πr

Plug in the values into the equation

Length of arc GH = 265/360 × 2 × π × 9.1

= 42.0886149

= 42.1 cm (nearest tenth)

6 0

2 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

3 0

2 years ago

9. Marika Perez's gross biweekly pay is $2,768.00 How much does she earn annually.

faust18 [17]

The answer is 71,968

5 0

2 years ago

Read 2 more answers

Which is the graph of the equation y-1=2/3(x-3)? <br> PLEASE ANSWER ASAP

alexgriva [62]

Answer:

Graph #1

Step-by-step explanation:

Compare your

y - 1 = (2/3)(x - 3) to

y - k = m(x - h). We see that k = 1 and h = 3.

Thus, (1, 3) is a point on the graph. This matches Graph #1.

Note: Graph #1 and Graph #3 appear to be the same. Why?

8 0

3 years ago

Read 2 more answers