Answer:
First choice:

Explanation:
<em>The probability that the first is a man's card and the second, a woman's card</em> is calculated as the product of both probabilities, taking into account the fact that the second time the number of cards in the hat has changed.
In spite of it is said that the cards are drawn at once, since it is stated a specific order for the cards (first is a man's card and the second, a woman's card) you can model the procedure as if the cards were drawn consecutively, instead of at once.
<u>1. Probability that the first is a man's card</u>
- Number of cards in the hat = 20 (the 20 business card)
- Number of man's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/20 = 1/2.
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<u>2. Probability that the second is a woman's card</u>
- Number of cards in the hat = 19 (there is one less card in the hat)
- Number of wonan's card in the hat: 10
- Probability = favorable oucomes / possible outcomes = 10/19.
<u>3. Probability that the first is a man's card and the second, a woman's card</u>
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That is the first choice.
Answer:
d. 94
Step-by-step explanation:
If business decreases 10%, it is 100% - 10% = 90% of normal.
If business decreases 30%, it is 100% -30% = 70% of normal.
if business is 94% of normal, it is not between these values, so is not a winter business statistic.
The concept useful in finding the answer to this item is ratio and proportion, the ratio of the height of your friend with the shadow casted should be proportional to the height of the rock with the length of the shadow it cast. That is,
5.5 ft / 18 ft = x ft/ 209.5 ft
The value of x from the equation above is 64 ft.
Answer:
C: p < 0.01
Step-by-step explanation:
We are given;
Spearman rank Correlation Coefficient: rs = 0.53
sample size: n = 13 pairs
Now, from the table attached, tracing n = 13 and locating a corresponding value of rs = 0.53 which falls in between 0.484 and 0.56. Thus, we can see that p is greater than the nominal significance value of 0.05 but less than 0.01.
Thus, correct answer is p < 0.01