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MrMuchimi
3 years ago
10

All trapezoids are parallelograms. A. True B. False

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

True

parallelogram is a quadrilateral with two pairs of parallel sides. A trapezoid has one pair of parallel sides .

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What is the length of AE<br><br> 1. 17.1<br> 2. 23.39<br> 3. 22.9<br> 4. 43.39
jonny [76]
I hope this helps you



17,1/17,1+20=20/20+AE


17,1/37,1=20/20+AE


171/371=20/20+AE

20+AE=20.371/171

20+AE=43,39

AE=23,39





4 0
3 years ago
Here is an equation 2x + 9 = -15. What are three different equations that have the same solution as that equation? Show or expla
Sliva [168]

To find those equations we can do any multiplication or division of both sides of the equation:

Examples:

2x + 9 = -15              | · 2

4x + 18 = -30

2x + 9 = -15              | · (-1)

-2x - 9 = 15

2x + 9 = -15               | ÷ 2

x + 4.5 = -7.5

There is the same solution: x = -12.

6 0
3 years ago
Name: Co
White raven [17]

Answer:

Thus last month Calvin made $414.90 from all the paintings sold at the art shows.

Step-by-step explanation:

Let us first analyse the given information in the question:

→ Small paints (lets call them s) sell for $25.80 Per Painting, thus:

  25.80s gives as the profit for s number paints sold.

→ Large paints (lets call them l) sell for $56.25 Per Painting, thus:

  56.25l gives as the profit for l number paints sold.

We also know last month he sold six large paintings and three small paintings thus from our variables above we can say:

s=3\\l=6         Eqn(1).

Thus the total profit of all paintings sold would be:

PROFIT= 25.80s+56.25l       which by pluggin in Eqn(1) values gives

PROFIT=25.80*3+56.25*6\\PROFIT=414.90

Thus last month Calvin made $414.90 from all the paintings sold at the art shows.

5 0
4 years ago
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
MariettaO [177]
The line through that point and the origin has a slope of -1. It is perpendicular to the line you want, so the line you want has slope +1. Its equation can be written as
.. y = (x -4) -4
or, in standard form
.. x - y = 8

5 0
3 years ago
Graphing rational functions. I need help asap!!!!
Anastaziya [24]

Answer:

1.  

Vert. asymptote: x = {-3, 2}

Horiz. asymptote: y = 0

x-int: None

Question 3.

a. There is no hole

b. Vert. asymptote: x = {-2, 2}

c. f(x) = 0: x = {0, -1/2}

d. The graph has no hole at (-2, 4)

Question 4.

a. Vert. asymptote: x = {-2, 2}

b. f(x) = 0: x = {0, -1/2}

c. Horizontal asymptote: y = 2

d. The graph has no hole

I'm a bit confused.  Some of the things stated in the question aren't true like how there are holes in places where there aren't.

6 0
3 years ago
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