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ivanzaharov [21]
3 years ago
15

Maths question that I need help with. I honestly dont understand a thing about prooving.

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

Answer:

i think angle a and o are 76

Step-by-step explanation:

180 - 28 =152 152/2=76

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The equation x^2+ y^2+ 8x - 12y + 43 = 0 is the equation of a circle. Complete the square to change this
egoroff_w [7]

Answer:

ans: centre of circle is ( -4 , 6 )

and radius is 3 unit

3 0
3 years ago
The area of a rectangular pool was 120square meters. If the long side in 7 meters plus a number and the width is 6 meters. What
NeX [460]

Answer:

The value of the variable=13 meters

Step-by-step explanation:

Step 1

Express the dimensions of the pool

Length=7+x

width=6

Step 2

Express the area of a rectangle as shown;

A=L×W

where;

A=area of a rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

A=120 m²

L=x+7

W=6

replacing in the equation;

120 m²=(x+7)×6

120=6 x+42

6 x+42=120

6 x=120-42

6 x=78

x=78/6

x=13

The value of the variable=x=13 meters

8 0
3 years ago
Work out the value of x.
tangare [24]

Answer:

The value of x could be anything, so I don't know what you mean until you have some sort of equation or graph - or anything at that.

Step-by-step explanation:

4 0
3 years ago
Find the length of side xz give your answers to 3 significant figures
aleksandrvk [35]

Answer:

XZ ≈ 14.4 cm

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos29° = \frac{adjacent}{hypotenuse} = \frac{ZY}{XZ} = \frac{12.6}{XZ}

Multiply both sides by XZ

XZ × cos29° = 12.6 ( divide both sides by cos29° )

XZ = \frac{12.6}{cos29} ≈ 14. 4 ( to 3 sig. figs )

3 0
3 years ago
A homeowner is installing a swimming pool in his backyard. he want its length to be 4 feet longer than its width. then he wants
marishachu [46]
1. You have that:

 - The homeowner<span> want the length of the swimming pool to be 4 feet longer than its width.</span> 
 - He wants to surround it with a concrete walkway 3 feet wide.
 - He can only afford 300 square feet of concrete for the walkway.

 2. Therefore, the tota area is:

 At=L2xW2

 L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
 W2 is the width of the walkway (W1+3+3⇒W2=W1+6)

 3. The area of the walkway is:

 A2=At-A1

 A2=300 ft²

 4. Therefore, you have that the width of the swimming pool is:

 A2=(W1+10)(W1+6)-(W1+4)(W1)
 300=(W1²+6W1+10W1+60)-(W1²+4W1)
 W1²+16W1+60-W1²-4W1-300=0
 12W1-240=0
 W1=240/12
 W1=20 ft

 5. And the length is:

 L1=W1+4
 L1=20+4
 L1=24 ft
8 0
3 years ago
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