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Nutka1998 [239]
4 years ago
9

I will give you branilest

Physics
2 answers:
morpeh [17]4 years ago
6 0

Answer:

Explanation:

if you bounce a tennis ball, it will come back up as an equal reaction to your action (dropping it). there is an equal but opposite reaction in this scenario, demonstrating newton's third law.

stich3 [128]4 years ago
3 0

Answer:

when u jump in the air and hit the ground the ground applies the same force back which applies a opposite force which causes u to propel into the air

Explanation:

hope this helped :)

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asambeis [7]

Answer:

TAJUK

Explanation:

Sebab saya suka makan ayam goreng, esok saya nak pesan daripada kedai pak abu, terima kasih bosku

6 0
3 years ago
How far will an object move in one second if it average speed is 5m/s?
Sphinxa [80]

The object will move 5 meters per second (5m/s)

3 0
4 years ago
Read 2 more answers
Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.
Vikentia [17]
The Newton’s law Nikolas would use to come up with this idea is the <span>Third law that states:

</span><span>When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.
</span>
So, in this case, let's name the first Body A which is the skateboard and the second body B which is <span>the compressed carbon dioxide in a fire extinguisher. Then, as shown in the figure below, according to the Third law:

</span>FA = -FB<span>

</span>

8 0
3 years ago
Read 2 more answers
True or false the hotter the star the higher is absolute magnitude?
liubo4ka [24]

Answer:

true

Explanation:

6 0
3 years ago
0/2 File Limit
slamgirl [31]

Answer:

Speed at which it will reach the ground is given as

v_f = 46.8 m/s

Total time for which it will remain in air is given as

t = 6.3 s

Explanation:

As we know that the object is projected upwards with speed

v_i = 15 m/s

g = - 9.81 m/s^2

now when it will reach the ground then we have

y = v_y t + \frac{1}{2} at^2

so we have

-100 = 15 t - \frac{1}{2}(-9.81) t^2

4.905 t^2 - 15 t - 100 = 0

so we have

t = 6.3 s

Now speed of the object when it reaches the ground is given as

v_f = v_i + at

v_f = -15 + (9.81)(6.3)

v_f = 46.8 m/s

8 0
4 years ago
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