I assume to give would be to spend a little longer catching the ball, this is done because the longer you take to change the velocity of something the less force you feel, another example of wanting to give would be a car crash, the longer you can absorb the hit the higher the chance of survival for the driver because the goal of giving in this scenario is to make the driver accelerate as slow as possible when crashing and a second example would be bending your knees when you fall because you make the time of impact longer reducing the amount of force you feel and also decreasing your odds of injury
Answer:
a) V = 6.52 10⁻⁵ V, b) Vb = 9.34 10⁻⁵ V
Explanation:
b) When using Gauss's law all the charge is considered concentrated in the inside of the sphere, for which the electrice field is
Q = 3.92 10⁻¹⁵ C
E = k Q / r²
Electric potential and electric field are related
E = - dV / dr
dV = - E dr
Vb-Va = - k Q (1 / rb -1 / ra)
Vb = - 8.99 10⁸ 3.92 10⁻¹⁵ 1 / 0.0377
Vb = 9.34 10⁻⁵ V
a) In this case we must know the electric field for the interior of the sphere, use Gauss's law, the charge inside is
ρ = Q / V
= ρ (4/3 π r³)
Ф = E A = Q_{int} /ε₀
E 4π r² = ρ 4/3 π r³ /ε₀
E = ρ r / 3ε₀
dV = ρ / 3ε₀ ∫ r dr
V = ρ / 3ε₀ r²
We evaluate between the center of the sphere V = 0 and the point R
V = ρ / 3ε₀ ½ (R²)
V = Q 3 / 4π R³ 3ε₀ (R²) = k Q 1 / 2R
V = 8.99 10⁸ 3.92 10⁻¹⁵ 1 / 0.027 2
V = 6.52 10⁻⁵ V
Answer:
+0.231 m/s
Explanation:
The problem can be solved by using the law of conservation of momentum. In fact, we have that the total momentum before the collision must be equal to the total momentum after the collision:
where we have
m1 = 245000 kg is the mass of the first car
m2 = 57500 kg is the mass of the second car
u1 = 0.513 m/s is the initial velocity of the first car
u2 = -0.125 m/s is the initial velocity of the second car
v = ? is the final velocity of the two cars together, after the collision
Solving the equation for v, we find
And the direction (positive sign) is the same as the initial direction of the first car.
Answer:
d. their color in a non-polar solvent
Explanation:
In non polar solvent such as cyclo hexane, halogens does not dilute, it rather maintains it's same or similar colour as it was in its concentrated form.
Halogens have 7 electrons in their outmost shells, examples includes chlorine, bromine, Iodine, astatine etc. They exist as room temperature.
Bromine exists as liquid.
Iodine as solid.
Chlorine as gas.