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Yuliya22 [10]
3 years ago
5

When is the zebra in motion? When is it not moving?

Physics
1 answer:
frosja888 [35]3 years ago
4 0
Motion depends on what your reference point is. So a good reference point is  a tree or a sign, something that is not moving. So if the zebra is walking towards the tree he/she is getting closer to the tree, He/she is in motion. But if the zebra and the tree never get closer or farther apart the zebra is not in motion. HOPE THIS HELPED!! ;D
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ozzi

Answer: The correct statements are:

  • The atoms are very attracted to one another.
  • The atoms are held tightly together.

Explanation:

Solid state: In this state, the molecules are closely packed and cannot move freely from one place to another that means no space between them and the intermolecular force of attraction between the molecules are strong.

In solid substance, the particles are very close to each other due to this the intermolecular forces of attraction are strongest.

The key point about solid are:

  • The atoms are very attracted to one another.
  • The atoms are not moving freely.
  • It will not spread out evenly to fill any container.
  • The atoms are held tightly together.
  • The forces of attraction are strong to bring molecules together.
  • The atoms are close and in fixed positions.
7 0
3 years ago
A piston–cylinder device initially contains steam at 3.5 MPa, superheated by 5°C. Now, steam loses heat to the surroundings and
velikii [3]

<u>Answer :</u>

(a) The Initial temperature of the steam is 247.557°C

(b) The enthalpy change per unit mass of the steam is -1771 kJ/kg

(c) The final pressure is 1555 kPa, and the liquid vapor mixture contains small mass of vapor.

<u>Explanation :</u>

From the given statements, we know

Initial steam pressure (P_1) = 3.5 MPa

Degree of Super heat = 5°C

Saturation Temperature (T_s_a_t) = 242.557°C [From Steam Table]

Now, the Initial temperature (T_1) of steam is given by-

T_1 = T_s_a_t + Degree of Superheat

 = 242.557 + 5 = 247.557°C

(b)To find: The enthalpy change per unit mass of the steam is  

We know enthalpy (h) change is given by

Δh = h_2 – h_1

From steam Table, properties of the gas at state 1 and state 2  

h_1 = 2821.1 kJ/kg

h_2 = 1049.7 kJ/kg

On substituting the values, we get

or, Δh = 1049.7 - 2821.1 = -1771 kJ/kg

(c) To Find: The final pressure of the liquid vapor mixture contains small mass of vapor.

We find that the gas at the final position, i.e., at position 3

Final Temperature (T_3) = 200°C [Given] ……………………………..(1)

Specific Volume (v_3) = Specific Volume (v_2) = 0.00123 m^3/kg ….....(2)

Using steam table for corresponding values of (1) and (2), we get

Final Pressure P_3 = 1555 kPa

Dryness fraction (x_3) = 0.0006.

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Answer:The gravitational field on Saturn can be calculated by the following formula;

Explanation:

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