Chromium , silver, zinc...
Answer
is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.
V(N₂O) = 8.4 L.
V(N₂O) =
n(N₂O) · Vm.
Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.
n(N₂O) = 8.4 L ÷ 22.4 L/mol.
n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>
Answer : The balanced chemical reaction will be:

Explanation :
Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.
It is represented as,

In this reaction, A is more reactive element and B is less reactive element.
As per question, when gold (IV) iodide react with bromine to give gold (IV) bromide and iodine.
The balanced chemical reaction will be:

Answer:
0.0702J/g°C the specific heat capacity of the metal.
Explanation:m

where,
Q = heat absorbed by metal = 186.75 J
= Mass of metal= 19 g
= Initial temperature of metal = 
=Final temperature of metal = 
= specific heat of metal= ?



0.0702J/g°C the specific heat capacity of the metal.
Answer:
The dilution factor of protein in tube # 4 is 125. Molar concentration is 0.0088 M protein
Explanation:
The dilution factor indicates how many times is more concentrated a main solution in relationship with a diluted solution. In this case, the main solution is in tube #1. For calculating the dilution factor and molar concentration in tube #4 we need the main solution concentration which comes from next equation:
Initial volume * initial concentration = final volume * final concentration
0.5 mL * 10M = 5mL * final concentration
1.1 M = final concentration = main solution concentration
Applying the same equation for remain tubes we have 0.22 M for tube #2, 0.044 M for tube # 4 and 0.0088 for tube # 4.
Dilution factor = Main solution concentration/tube 4 concentration
Dilution factor = 1.1/0.0088 = 125
I hope my answer helps you