Answer:
The heat needed to boil 1 gallon of water is 81,490.62 Joules.
Explanation:
![Q=mc\Delta T](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T)
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have :
Volume of water = V = 1 gal = 4546.09 mL
Density of water , d= 1 g/mL
mass of water = m = d × V = 1g/mL × 4546.09 mL = 4546.09 g
Specific heat of water = c = 1 Cal/g°C
ΔT = 100°C - 25°C = 75 °C
9 (boiling pint of water is 100°C)
Heat absorbed by the water to make it boil:
![Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal](https://tex.z-dn.net/?f=Q%3D%204546.09%20g%5Ctimes%201%20Cal%2Fg%5EoC%5Ctimes%2075%5EoC%3D340%2C956.75%20Cal)
1 calorie = 4.184 J
![Q=\frac{340,956.75}{4.184} J = 81,490.62 J](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B340%2C956.75%7D%7B4.184%7D%20J%20%3D%2081%2C490.62%20J)
The heat needed to boil 1 gallon of water is 81,490.62 Joules.