Ask question

Ask question

All categories

uranmaximum [27]

3 years ago

15

Identify at least three control variables that could be used with this investigation: What temperature allows for bacterial grow

th to occur quickly?

2 answers:

Olenka [21]3 years ago

7 0

Answer:

whats the expirement

Explanation:

Over [174]3 years ago

6 0

Answer:

Time allowed for incubation, size of the dish, the amount of light, amount of agar, the type of agar…etc

Explanation:

You might be interested in

What is the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP)?

baherus [9]

1 mole ----------- 22.4 L ( at STP )
3.5 mols --------- ?

V = 3.5 x 22.4 / 1

V = 78.4 L

hope this helps!

4 0

3 years ago

Write two reactions showing nascent Hydrogen is more reactive than<br> molecular Hydrogen.

ratelena [41]

Answer:

1.) Nascent Hydrogen has more energy than Molecular Hydrogen.

2.) Nascent Hydrogen is are more on the side of atomic and since atoms are more active than molecules, Nascent Hydrogen becomes more reactive.

4 0

3 years ago

On a trip of 555 miles, an automobile consumed 55.5 gallons of gasoline costing $4.55 per gallon.

bagirrra123 [75]

Answer:

0.455

Explanation:

555/55.5 mean 10 miles per gallon, take the price per gallon and divide it by 10. 4.55/10

5 0

3 years ago

Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0

3 years ago

Forces that change an object motion by touching the object are _______ forces

strojnjashka [21]

Forces are pushes and pulls that may change the motion of an object. Balanced forces result in an object remaining at rest or moving at a constant speed. Unbalanced forces result in the acceleration of an object. An object's motion depends on how it changes position.

7 0

3 years ago