Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.
Answer:
It is less than 25m/s as the correct average is 24m/s.
Explanation:
This is becuase you need to take the average of the two speeds (18m/s and 30m/s) 18 + 30 divided by 2 is 24m/s.
Neptune is one of two ice giants in the outer solar system (the other is Uranus). Most (80 percent or more) of the planet's mass is made up of a hot dense fluid of "icy" materials—water, methane and ammonia—above a small, rocky core. Of the giant planets, Neptune is the densest.
Pls mark brainliest
Answer:
a) fr = 266.92 N, fy = 1300 N, b) μ = 0.36
Explanation:
a) This is a balancing act.
Let's write the rotational equilibrium relations, where the turning point is the bottom of the ladder and the counterclockwise rotations are positive
-w x - W x₂ + R y = 0 (1)
usemso trigonometry to find distances
cos 60.08 = x / 7.5
x = 7.5 cos 60.08
x = 3.74 m
fireman
cos 60.08 = x₂ / 4
x2 = 4 cos 60
x2 = 2 m
wall support
sin 60.08 = y / 15
y = 15 are 60.08
y = 13 m
we substitute in equation 1
R y = w x + W x2
R = (w x + W x2) / y
R = (500 3.74 +800 2) / 13
R = 266.92 N
now let's write the expressions for the translational equilibrium
X axis
R -fr = 0
R = fr
fr = 266.92 N
Y Axis
Fy - w-W = 0
fy = 500 + 800
fy = 1300 N
b) ask the friction coefficient
the firefighter's distance is
cos 60.08 = x₃ / 9.00
x₃ = 9 cos 60
x₃ = 5.28 m
from equation 1
R = (w x + W x₃) / y
R = 500 3.74 + 800 5.28) / 13
R = 468.769 N
we saw that
fr = R = 468.769
The expression for the friction force is
fr = μ N
in this case the normal is the ratio to pesos
N = Fy
N = 1300 N
μ N = fr
μ = fr / N
μ = 468,769 / 1300
μ = 0.36
Answer:
40.47m/s²
Explanation:
Acceleration is the change in velocity of a body with respect to time.
Acceleration = change in velocity/time
Given speed = 1020km/hr
Time = 1.7s
Converting 1020km/hr to m/s we have;
(1020×1000/3600)m/s
= 1,020,000/3,600
= 283.3m/s
Acceleration = 283.3/7
Acceleration = 40.47m/s²
Deceleration is therefore 40.47m/s²