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Bumek [7]
3 years ago
12

Which of the following is NOT a result of supernova explosions? The neutron core is completely destroyed. Any planets within a f

ew dozen light-years receive a life-threatening dose of radiation. Many of the elements the star fused during its life are blasted out into space. Many new elements, including some heavier than iron, are fused during the supernova explosion.
Physics
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

 The neutron core is completely destroyed

Explanation:

 A earth - supernova is an explosion resulting to the death of a star that occurs close enough to the earth but this does not completely destroy a star. Supernovae are the most violent explosions in the universe. But they do not explode like a bomb explodes, blowing away every bit of the original bomb. Rather, when a star explodes into a supernova, its core survives. The reason for this is that the explosion is caused by a gravitational rebound effect and not by a chemical reaction. Stars are so large that the gravitational forces holding them together are strong enough to keep the nuclear reactions from blowing them apart. It is the gravitational rebound that blows apart a star in a supernova.

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A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.24 m/s2 for 10.0 s. 2
valentina_108 [34]

Answer:

1817.448 m

Explanation:

Given:

Initial acceleration = 2.24 m/s²

Time for acceleration = 10 s

From  Newton's equation of motion

v = u + at

here v is the final velocity after the acceleration

v = 0 + 2.24 × 10 = 22.4 m/s

thus,

the displacement during acceleration

From  Newton's equation of motion

s_1=ut+\frac{1}{2}at^2

where,  

s is the distance

u is the initial speed = 0 m/s as starting from rest

a is the acceleration

t is the time

on substituting the respective values, we get

s_1=0\times10+\frac{1}{2}\times2.24\times10^2

or

s₁ = 112 m

for case 2

time = 1.25 minute = 1.25 × 60 = 75 seconds

displacement, s₂ = v × t = 22.4 × 75 = 1680 m

for the case 3

acceleration = - 9.86 m/s²

now,

the final velocity for the second case is the initial velocity for this case

thus,

s_3=22.4\times2.27+\frac{1}{2}(-9.86)\times2.27^2

or

s₃ = 50.848 - 25.40 = 25.448 m

hence,

the total displacement = s₁ + s₂ + s₃ = 112 m + 1680 m + 25.448 m

= 1817.448 m

3 0
4 years ago
A sprinter speeds up to 3 m/s during the last 2 seconds of the race with an
quester [9]

Answer:

<em>The initial speed of the sprinter was 2.2 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The following relation applies:

v_f=v_o+at

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of a=0.4~m/s^2.

To find the initial speed, we solve the equation for vo:

v_o=v_f-at

Substituting the values:

v_o=3-0.4*2

v_o=3-0.8

v_o=2.2~m/s

The initial speed of the sprinter was 2.2 m/s

4 0
3 years ago
A diver shines a flashlight upward from beneath the water (n = 1.33) at a 32.7° angle to the vertical. At what angle does the li
suter [353]

Answer:

45.93°

Explanation:

The angle of incidence is given as 32.7°

The refractive index of the water that is n_1=1.33

Refractive index of the air that is n_2=1 (because the refractive index of air is 1 )

We have to find the angle at which the light leave the water means angle of refraction

So according to snell's law n_1sini=n_2sinr

1.33sin32.7=1\times sinr

sinr=0.7185

r =45.93°

So the light leave the water at an angle of 45.93°

3 0
4 years ago
The average adult in the US watches _____ hours of television each week.
Shkiper50 [21]
The average adult in the us spends 24 hours watching televistion each week
8 0
4 years ago
Read 2 more answers
A 25.0 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic frictio
Alekssandra [29.7K]

Answer:

The minimum angle at which the box starts to slip (rounded to the next whole number) is α=19°

Explanation:

In order to solve this problem we must start by drawing a sketch of the problem and its corresponding fre body diagram (See picture attached).

So, when we are talking about friction, there are two types of friction coefficients. Static and kinetic. Static friction happens when the box is not moving no matter what force you apply to it. You get to a certain force that is greater than the static friction and the box starts moving, it is then when the kinetic friction comes into play (kinetic friction is generally smaller than static friction). So in order to solve this problem, we must find an angle such that the static friction is the same as the force applie by gravity on the box. For it to be easier to analyze, we must incline the axis of coordinates, just as shown on the picture attached.

After doing an analysis of the free-body diagram, we can build our set of equations by using Newton's thrid law:

\sum F_{x}=0

we can see there are only two forces in x, which are the weight on x and the static friction, so:

-W_{x}+f_{s}=0

when solving for the static friction we get:

f_{s}=W_{x}

We know the weight is found by multiplying the mass by the acceleration of gravity, so:

W=mg

and:

W_{x}=mg sin \alpha

we can substitute this on our sum of forces equation:

f_{s}=mg sin \alpha

the static friction will depend on the normal force applied by the plane on the box, static friction is found by using the following equation:

f_{s}=N\mu_{s}

so we can substitute this on our equation:

N\mu_{s}=mg sin \alpha

but we don't know what the normal force is, so we need to find it by doing a sum of forces in y.

\sum F_{y}=0

In the y direction we got two forces as well, the normal force and the force due to gravity, so we get:

N-W_{y}=0

when solving for N we get:

N=W_{y}

When seeing the free-body diagram we can determine that:

W_{y}=mg cos \alpha

so we can substitute that in the sum of y-forces equation, so we get:

N=mg cos \alpha

we can go ahead and substitute this equation in the sum of forces in x equation so we get:

mg cos \alpha \mu_{s}=mg sin \alpha

we can divide both sides of the equation into mg so we get:

cos \alpha \mu_{s}=sin \alpha

as you may see, the angle doesn't depend on the mass of the box, only on the static coefficient of friction. When solving for \mu_{s} we get:

\mu_{s}=\frac{sin \alpha}{cos \alpha}

when simplifying this we get that:

\mu_{s}=tan \alpha

now we can solve for the angle so we get:

\alpha= tan^{-1}(\mu_{s})

and we can substitute the given value so we get:

\alpha= tan^{-1}(0.350)

which yields:

α=19.29°

which rounds to:

α=19°

8 0
4 years ago
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