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Bumek [7]
3 years ago
12

Which of the following is NOT a result of supernova explosions? The neutron core is completely destroyed. Any planets within a f

ew dozen light-years receive a life-threatening dose of radiation. Many of the elements the star fused during its life are blasted out into space. Many new elements, including some heavier than iron, are fused during the supernova explosion.
Physics
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

 The neutron core is completely destroyed

Explanation:

 A earth - supernova is an explosion resulting to the death of a star that occurs close enough to the earth but this does not completely destroy a star. Supernovae are the most violent explosions in the universe. But they do not explode like a bomb explodes, blowing away every bit of the original bomb. Rather, when a star explodes into a supernova, its core survives. The reason for this is that the explosion is caused by a gravitational rebound effect and not by a chemical reaction. Stars are so large that the gravitational forces holding them together are strong enough to keep the nuclear reactions from blowing them apart. It is the gravitational rebound that blows apart a star in a supernova.

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What is the relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum? As t
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<u>Explanation</u>

  • The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.

                STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE

                WAVE NUMBER SINGLE>DOUBLE>TRIPLE

  • wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).

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What is a covalent bond considered
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When solid surfaces slide over each other, the kind of friction that occurs is called_____ friction.
expeople1 [14]

Answer:

Sliding Friction

Explanation:

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7 0
3 years ago
Read 2 more answers
Find the ratio of the lengths of the two mathematical pendulums, if the ratio of periods is 1.5​
juin [17]

Answer:

The ratio of lengths of the two mathematical pendulums is 9:4.

Explanation:

It is given that,

The ratio of periods of two pendulums is 1.5

Let the lengths be L₁ and L₂.

The time period of a simple pendulum is given by :

T=2\pi \sqrt{\dfrac{l}{g}}

or

T^2=4\pi^2\dfrac{l}{g}\\\\l=\dfrac{T^2g}{4\pi^2}

Where

l is length of the pendulum

l\propto T^2

or

\dfrac{l_1}{l_2}=(\dfrac{T_1}{T_2})^2 ....(1)

ATQ,

\dfrac{T_1}{T_2}=1.5

Put in equation (1)

\dfrac{l_1}{l_2}=(1.5)^2\\\\=\dfrac{9}{4}

So, the ratio of lengths of the two mathematical pendulums is 9:4.

3 0
3 years ago
2. What is the speed of section A? Section B? Section C?
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