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lana66690 [7]
3 years ago
13

A skydiver jumps from an airplane traveling 120. km/hr at a height of 1000. m. If his parachute must open 500. m above the groun

d, how long does he have for the chute to open?
Physics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer:

The parachute to open in 15 sec.

Explanation:

Given that,

Velocity = 120 km/hr

Height = 1000 m

If his parachute must open 500. m above the ground.

We need to calculate the time for parachute to open

Using formula of time

v=\dfrac{d}{t}

t=\dfrac{d}{v}

Where, d = distance

t = time

v = velocity

Put the value into the formula

t=\dfrac{500}{120\times\dfrac{5}{18}}

t=15\ sec

Hence, The parachute will be open in 15 sec.

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Answer:

The object is most likely to be a (distant) galaxy

Explanation:

Distance of galaxies are often calculated based on the unit of light year.

The abbreviation, mpc which translates to mega parsec

A mega parsec is equivalent to 3.3 light years.

So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy

8 0
3 years ago
What is the acceleration of a car that starts from rest and achieves a speed of 45 m/s in 5 seconds?
bagirrra123 [75]

Answer:

9m/s^2

Explanation:

solution,

Given. Initial velocity (u)=0m/s

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Time taken(t)=5sec

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we know,

a=v-u/t

=45-0/5

=45/5

=9m/s^2

Therefore acceleration (a)= 9m/s^2

4 0
2 years ago
The muzzle velocity of a 50.0g shell leaving a 3.00 kg rifle is 400m/s what is the recoil velocity of the rifle
serg [7]

Here if we consider bullet and gun as a system then we can say that momentum of the system will remain conserved

so we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now we know that

m_1 = 50 g = 0.050 kg

m_2 = 3 kg

v_{1i} = v_{2i} = 0

v_{1f} = 400 m/s

now we will have

0.050(0) + 3(0) = 0.050(400) + 3(v)

20 + 3v = 0

v = - \frac{20}{3} = - 6.67 m/s

so gun will recoil with speed 6.67 m/s

6 0
3 years ago
A stone is dropped from top of a tower. If it takes 6 sec to hit the ground, find the height of tower and velocity with which th
-Dominant- [34]

Answer:

Explanation:

s = ut+ 0.5at²

u = 0

t = 6

a = 9.81

s = 0 + 0.5 * 9.81 * 36 = 176.58 m

v = u + at

v = 9.81* 36 = 353 m/s

4 0
2 years ago
PLZ hurry! Thank you
Alenkinab [10]

Answer:do it again

Explanation:

It will work

3 0
3 years ago
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