Answer:
The object is most likely to be a (distant) galaxy
Explanation:
Distance of galaxies are often calculated based on the unit of light year.
The abbreviation, mpc which translates to mega parsec
A mega parsec is equivalent to 3.3 light years.
So, if the astronomer sighted the object from a distance of 28mpc which is equivalent to 28 * 3.3 light-years (92.4 light years); the object is most likely to be a galaxy; a distant galaxy
Answer:
9m/s^2
Explanation:
solution,
Given. Initial velocity (u)=0m/s
Final velocity (v)=45m/s
Time taken(t)=5sec
Acceleration (a)=?
we know,
a=v-u/t
=45-0/5
=45/5
=9m/s^2
Therefore acceleration (a)= 9m/s^2
Here if we consider bullet and gun as a system then we can say that momentum of the system will remain conserved
so we will have

now we know that




now we will have



so gun will recoil with speed 6.67 m/s
Answer:
Explanation:
s = ut+ 0.5at²
u = 0
t = 6
a = 9.81
s = 0 + 0.5 * 9.81 * 36 = 176.58 m
v = u + at
v = 9.81* 36 = 353 m/s