All categories

3 years ago

18-A tire rotates at a constant 1.7 radians angle every 0.15 s. A) What is the tire's angular 2 points

Physics

1 answer:

aliya0001 [1]3 years ago

5 0

Explanation:

A) use the formula:

$angular \: velocity = angular \: dispacement \div time$

B) use the formula:

$linear \: velocity = radius \times angular \: velocity$

with angular velocity u calculated in A)

You might be interested in

While sitting on the couch, I am pushing down on it and it is pushing up on me. Which of Newton's laws of motion is this demonst

ArbitrLikvidat [17]

The third law of motion. Every action has an equal and opposite reaction. You exert a force on it and it exerts it back.

7 0

3 years ago

Read 2 more answers

Complete the mechanism for the given decarboxylation by adding any missing atoms, bonds, charges, nonbonding electrons, and curv

AlexFokin [52]

The decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

<h3>What is a decarboxylation reaction?</h3>

A decarboxylation reaction is one in which the carboxyl group in a carboxylic acid is replaced with hydrogen.

In living organisms, decarboxylation reactions are catalyzed by enzymes called decarboxylases or carboxy-lyases.

The decarboxylation of beta-carbonyl esters proceeds through a cyclic transition state giving an enol intermediate which then tautomerises to the carbonyl.

Therefore, a decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

Leran more about decarboxylation at: brainly.com/question/893601

5 0

2 years ago

Which atomic particle gives an atom gives it it’s chemical properties? Question 3 options: A.Isotopes B.Neutrons C.Electrons D.P

bulgar [2K]

C. is your answer! Hope it helps!

7 0

3 years ago

Read 2 more answers

Which sentence uses the correct adverb to make a comparison?

Arturiano [62]

Option C would be the right one

8 0

3 years ago

Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a

allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s$

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

$v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2$

Acceleration of the frog is 2874.33 m/s²

6 0

4 years ago