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artcher [175]
3 years ago
11

A pebble drops from a balcony that is 80 feet above the ground. The pebble lands on the top of a sign that is 16 feet high. The

function y=80−16t2 represents the height y (in feet) of the pebble t seconds after dropping from the balcony. How many seconds does the pebble drop before hitting the sign?
The pebble hits the sign after ______ seconds.
Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

t =2 seconds

Step-by-step explanation:

We have, a function that represents the height y of the pebble after dropping the balcony as follows :

y=80-16t^2

The pebble lands on the top of a sign that is 16 feet high.

It is required to find the time does the pebble drop before hitting the sign. The above equation becomes,

80-16t^2=16\\\\-16t^2+80=16\\\\-16t^2=64\\\\t^2=4\\\\t=2

So, the pebble hits the sign after 2 seconds.

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10 is not a multiple of 3 so no 6/10 is not multiples for 3/10 and 6 is not a mutiple of 10 so it can't be also the same with 6/30 although 6/30 is multiples for 3 but 6 is not a mutiple for 10.
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Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

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In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

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\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

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Answer:

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Step-by-step explanation:

hope this helps

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The perimeter of a parallelogram is 72 meters.The width of the parallelogram is four meters less than its length. Find the lengt
Naya [18.7K]
Parallelogram have 4 sides.

Use the distributive property. 2 multiply the last and negative 4 in the parentheses.
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l= 20

The width of the parallelogram is four meters less than its length.

4 sides
2 length = 20
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I got 16 by subtracting 4 from 20

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