Hey There!
To find the rate of change, simply use the following formula.
y2 - y1 = x2 - x1
Keeping this in mind, let's begin to solve.
3 - 4 = -1
1 - (-1) = 2
Therefore, the answer would be C
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The point on a number line is the location of the point.
<h3>How to draw the number line</h3>
The points are given as:
x = 10 and x = 0
This means that we mark a point at the point 10 on the number line, and another point at the point 0 on the same number line
However, the point 0 would come before point 10 because 0 is less than 10
See attachment for the number line
Read more about number lines at:
brainly.com/question/10851163
<h3>
Answer: Choice B</h3>
The parent function y = sqrt(x) has the point (0,0) on it. When we subtract 3, we get y = sqrt(x)-3 which moves the point (0,0) three units down to get to (0,-3)
So (0,-3) is one point on y = sqrt(x)-3
<span>You can probably just work it out.
You need non-negative integer solutions to p+5n+10d+25q = 82.
If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80.
So this is the same as n + 2d + 5q ≤ 16
So now you simply have to "crank out" the cases.
Case q=0 [ n + 2d ≤ 16 ]
Case (q=0,d=0) → n = 0 through 16 [17 possibilities]
Case (q=0,d=1) → n = 0 through 14 [15 possibilities]
...
Case (q=0,d=7) → n = 0 through 2 [3 possibilities]
Case (q=0,d=8) → n = 0 [1 possibility]
Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81
Case q=1 [ n + 2d ≤ 11 ]
Case (q=1,d=0) → n = 0 through 11 [12]
Case (q=1,d=1) → n = 0 through 9 [10]
...
Case (q=1,d=5) → n = 0 through 1 [2]
Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42
Case q=2 [ n + 2 ≤ 6 ]
Case (q=2,d=0) → n = 0 through 6 [7]
Case (q=2,d=1) → n = 0 through 4 [5]
Case (q=2,d=2) → n = 0 through 2 [3]
Case (q=2,d=3) → n = 0 [1]
Total from case q=2: 1 + 3 + 5 + 7 = 16
Case q=3 [ n + 2d ≤ 1 ]
Here d must be 0, so there is only the case:
Case (q=3,d=0) → n = 0 through 1 [2]
So the case q=3 only has 2.
Grand total: 2 + 16 + 42 + 81 = 141 </span>
Answer:
15 and 27 are composite
Step-by-step explanation:
prime numbers only factor into 1(x) and x(1)
13 = 1(13), 13(1)
15 = 1(15), 3(5), 5(3), 15(1)
17 = 1(17), 17(1)
27 = 1(27), 3(9), 9(3), 27(1)
hope this helps
