Answer:
Make the question more clear for me
Explanation:
For #4 first find the molar mass(M) of copper then use that and the mass (m) n=m/M to find moles(n) using moles and the volumes find the concentration using c=n/V
Answer:
Lmol⁻¹s⁻¹
Explanation:
The rate law of the given reaction is:-
Rate=k[A][B]
Wherem, k is the rate constant.
Given that:-
Rate = 0.36 mol/Lsec = 0.36 M/sec
[A] = 3.0 M
[B] = 1.0 M
Thus,
Applying in the equation as:-
0.36 M/sec =k × 3.0 M× 1.0 M
k = 0.12 (Ms)⁻¹ = 0.12 Lmol⁻¹s⁻¹
<u>The units of k = Lmol⁻¹s⁻¹</u>
Answer:
D
Explanation:
Reduction refers to gain in electrons. Hence it is D
Oxidation occurs when the element loses electrons. Hence A is wrong
Answer:
3.657 kg
Explanation:
Given:
Enthalpy of combustion of hard coal = -35 kJ/g
Enthalpy of combustion of gasoline = 1.28 × 10⁵ kJ/gal
Density of gasoline = 0.692 g/mL
now,
The heat provide 1 gallon of gasoline provide = 1.28 × 10⁵ kJ
and,
heat provided by the 1 gram of coal = 35 kJ
or
1 kJ of heat is provided by (1/35) gram of hard coal
therefore,
For 1.28 × 10⁵ kJ of heat, mass of hard coal = 1.28 × 10⁵ kJ × (1 / 35)
or
For 1.28 × 10⁵ kJ of heat, mass of hard coal = 3657.14 grams = 3.657 kg
