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3 years ago

7. In how many ways can the same 5-question True / False quiz be

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

Answer:

243 ways

Step-by-step explanation:

Calculating the number of posible outcomes:

We have n trials.

Each trial has m possible outcomes.

The total number of outcomes is:

$T = m^{n}$

In this question:

5 questions, that is, 5 trials, so $n = 5$

Each question has 3 options(True, false or unanswered). So $m = 3$

How many ways?

$T = 3^{5} = 243$

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During a trip, a driver travelled a distance of 80km at an average speed of 60km/hr.He then changed his speed and travelled the

oksian1 [2.3K]

Answer:

50 km/hr

Step-by-step explanation:

D = RT

Time for first part of trip = 80/60 = 4/3 hr.

Time for second part of trip = 20/30 = 2/3 hr.

total time for entire trip = 4/3 + 2/3 = 6/3 = 2 hr.

Total distance = 100 km

Average rate of speed for entire trip = 100/2 = 50 km/hr

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3 years ago

Two 6-sided dice are rolled. What is the probability that the sum is odd and the number on one of the dice is a 1?

Colt1911 [192]

Answer:

For knowing what the probability will be, you need to see the dice individually.

The probability that dice 1 will get a 1, is 1/6.

The probability that dice 2 will get an odd number, is 3/6 or 1/2.

Now what is the probability that those two both come true?

I have no clue maybe multiply both and then you will get something like;

1/6.1/2 = 1/12

8 0

3 years ago

What would the equation be for a quadratic equation with a vertex of (-5,-2)?

natta225 [31]

The quadratic equation could be: $y=(x+5)^2-2$

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4 years ago

Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin

Brums [2.3K]

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470 Eqn 1

x = y+14 Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330$

Dividing both sides by 30

$\frac{30y}{30}=\frac{330}{30}\\y=11$

Putting y=11 in Eqn 2

$x=11+14\\x=25$

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

∫x(x-6)³dx by using substitution u=x-6

Agata [3.3K]

Answer:

$\large\boxed{\int\bigg(x(x-6)^3\bigg)dx=\dfrac{1}{5}(x-6)^5+\dfrac{3}{2}(x-6)^4+C}$

Step-by-step explanation:

$\int\bigg(x(x-6)^3\bigg)dx\Rightarrow\left[\begin{array}{ccc}x-6=u\\x=u+6\\dx=du\end{array}\right]\Rightarrow\int\bigg((u+6)u^3\bigg)du\\\\=\int(u^4+6u^3)du=\dfrac{1}{5}u^5+\dfrac{6}{4}u^4+C=\dfrac{1}{5}(x-6)^5+\dfrac{3}{2}(x-6)^4+C$

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4 years ago