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jeka57 [31]
3 years ago
8

7. In how many ways can the same 5-question True / False quiz be

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0

Answer:

243 ways

Step-by-step explanation:

Calculating the number of posible outcomes:

We have n trials.

Each trial has m possible outcomes.

The total number of outcomes is:

T = m^{n}

In this question:

5 questions, that is, 5 trials, so n = 5

Each question has 3 options(True, false or unanswered). So m = 3

How many ways?

T = 3^{5} = 243

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Soloha48 [4]
The general term of the series is 

t(n)  =  1/ sin xsin ( x+1)

Now expand sin (x + 1) using sin (a + B), simplify, and you will get around 57.14

Hope this helps
3 0
4 years ago
Find an equation for the line with an x-intercept of 4 and y-intercept of -2
Bumek [7]

Answer:

Step-by-step explanation:

The x-intercept exists when y = 0; the coordinate that results from our x-intercept is (4, 0).

The y-intercept exists when x = 0; the coordinate that results from our y-intercept is (0, -2).

We can use these 2 coordinates to find the slope of the line we need to write:

m=\frac{-2-0}{0-4}=\frac{1}{2}

Now we can use that slope along with one of our points to write the equation of the line.  I am going to use the point-slope form, then we will solve it for y to put it into slope-intercept.  Let's use the coordinate (4, 0).  Keep in mind that regardless of which point we choose to use to write our equation, we will get the same equation.

y - 0 = 1/2(x - 4) and

y = 1/2x - 2

That's your equation!

6 0
3 years ago
Factor theorem ...first part​
ira [324]

Answer:

(-∞, -2) and (2, ∞)

Step-by-step explanation:

ƒ(x) = x³ -12x + 10

f'(x) = 3x² - 12  

Set 3x² - 12 = 0

        x² -  4 = 0

              x² = 4

               x = ±2

The points x = -2 and x = + 2 divide the number line into three intervals:

(-∞, -2), (-2, +2), and (+2, ∞).

a. Interval (-∞, -2)

x < -2, so f'(x) > 0 when -∞ < x < -2

The function is increasing in (-∞, -2).

b. Interval (-2, 2)

|x| < 2, so f'(x) <0

The function is decreasing in (-2, 2).

c. Interval (2, ∞)

x > 2, so f'(x) > 0 when 2 < x < ∞

The function is increasing in (2, ∞).

Thus, the function is increasing in the intervals (-∞, -2) and (2, ∞).

8 0
3 years ago
Show all of your work, even though the question may not explicitly remind you to do so. Clearly label any functions, graphs, tab
natta225 [31]

Answer:

  (a) at t=2, the particle is moving toward the origin

  (b) a(t) = 70(8 -9t^2)/(3t^2 +8)^3; a(2) = -0.245

  (c) the particle approaches x = 1/3 as t gets large

Step-by-step explanation:

(a) The function x(t) is negative for -3 < t < 3, so at t = 2, the particle is to the left of the origin.

The velocity of the particle is given by the derivative of the position function:

  x'(t)=\dfrac{(3t^2+8)(2t)-(t^2-9)(6t)}{(3t^2+8)^2}=\dfrac{70t}{(3t^2+8)^2}

Then, at t=2, the expression is positive, indicating the particle is moving toward the origin.

__

(b) The acceleration is the derivative of the velocity, so is ...

  a(t)=\dfrac{70(3t^2+8)^2-(70t)(12t)(3t^2+8)}{(3t^2+8)^4}=\dfrac{70(3t^2+8-12t^2)}{(3t^2+8)^3}\\\\\boxed{a(t)=\dfrac{70(8-9t^2)}{(3t^2+8)^3}}

Then at t=2, the acceleration is ...

  a(2) = 70(8 -9·4)/(3·4+8)^3 = 70(-28)/8000

  a(2) = -0.245

__

(c) As t gets large, the value of x(t) approaches t^2/(3t^2) = 1/3.

7 0
4 years ago
6/16=9/x what is the value of x​
Olenka [21]

Answer:

6/16=9/x

that would be 24

6 0
3 years ago
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