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3 years ago

What is the distance if traveling 6.5 m/s for 25 seconds

Chemistry

1 answer:

Nesterboy [21]3 years ago

4 0

Explanation:

In this problem, we are given a conversion factor.

$6.5 m=1s$

So, since we know this, we can simply multiply 25 by 6.5 to see what the distance will be.

25 * 6.5 = 162.5

So, the distance traveled for 25 seconds is 162.5 miles.

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Paraphin [41]

<h2>Answer: C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

<h3> ∴ 1s²2s²2p⁶ is the noble gas (neon)</h3>

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3 years ago

What group is nickel in?<br> O2<br> 010<br> O 15<br> O4

Ronch [10]

Answer:

010

Explanation:

Group 10

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4 years ago

The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the li

Agata [3.3K]

Answer:

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

<em>Which statement below explains that?</em>

<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.

<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.

<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.

<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.

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3 years ago

The pH of 0.10 M solution of an acid is 6. What is the acid dissociation constant of the acid?

svlad2 [7]

Answer: Dissociation constant of the acid is $10^{-11}$ .

Explanation: Assuming the acid to be monoprotic, the reaction follows:

$HA\rightleftharpoons H^++A^-$

pH of the solution = 6

and we know that

$pH=-log([H^+])$

$[H^+]=antilog(-pH)$

$[H^+]=antilog(-6)=10^{-6}M$

As HA ionizes into its ions in 1 : 1 ratio, hence

$[H^+]=[A^-]=10^{-6}M$

As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:

$[HA]=[HA]-[H^+]$