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Sav [38]
3 years ago
10

What is the distance if traveling 6.5 m/s for 25 seconds

Chemistry
1 answer:
Nesterboy [21]3 years ago
4 0

Explanation:

In this problem, we are given a conversion factor.

6.5 m=1s

So, since we know this, we can simply multiply 25 by 6.5 to see what the distance will be.

25 * 6.5 = 162.5

So, the distance traveled for 25 seconds is 162.5 miles.

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Which atoms are<br> forming a solid?
Marat540 [252]

Answer:

the third one

Explanation:

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3 years ago
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Help me with homework.
andrey2020 [161]

The chemical equation is said to be balanced if the number of atoms in the reactants and products is the same

<h3>Further explanation</h3>

Equation balanced ⇒ total number of atoms in reactants(on the left)= total number of atoms in products(on the right)

H₂+O₂---> H₂O

Reactants : H₂, O₂

Products : H₂O

not balanced

H₂O₂ ---> H₂O+O₂

Reactants : H₂O₂

Products : H₂O, O₂

not balanced

Na+O₂ ---> Na₂O

Reactants : Na, O₂

Products :  Na₂O

not balanced

N₂+H₂ ---> NH₃

Reactants : N₂, H₂

Products :  NH₃

not balanced

P₄+O₂---> P₄O₁₀

Reactants : P₄, O₂

Products :  P₄O₁₀

not balanced

Fe+H₂O ----> Fe₃O₄ + H₂

Reactants : Fe, H₂O

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7 0
3 years ago
Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0
3 years ago
Is the following nuclear equation balanced?<br><br> No<br> Yes
fredd [130]

Answer:

Yes.

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Therefore, the equation will be reduced to:

226 - 4 = 222

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Explanation:

7 0
3 years ago
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Natural atom of the same element may have the same _________?
Minchanka [31]

Answer:B

Explanation:

4 0
3 years ago
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