Answer:
I would expect the gas rate determined in this manner to be too low
Explanation:
A Rotameter can be designed to respond to the sensitivity of density, velocity, to measure the flow rate of liquid or gas enclosed in a tube. Liquids are denser than gas, and since the gas rate to be determined needed to respond to the velocity head alone of the rotameter so as to bring the forces in the tube equilibrium. Knowing if there is no flow, then the float would remain at the bottom, so gas has to flow at a higher rate compared to the liquid so the float would be in a similar position making it easier to measure the flowrate. This leaves the gas rate to be determined too low.
Answer:
a)CH₄, BH₃, and CCl₄
Explanation:
<u>London dispersion forces:-
</u>
The bond for example, in the molecule is F-F, which is non-polar in nature because the two fluorine atoms have same electronegativity values.
The intermolecular force acting in the molecule are induced dipole-dipole forces or London Dispersion forces / van der Waals forces which are the weakest intermolecular force.
Out of the given options, H₂O , NH₃ exhibits hydrogen bonding which is:-
<u>Hydrogen bonding:-
</u>
Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.
Thus option B and C rules out.
<u>Hence, the correct option which represents the molecules which would exhibit only London forces is:- a)CH₄, BH₃, and CCl₄</u>
<u>Answer:</u> The temperature increase will be 31.70°C.
<u>Explanation:</u>
To calculate the increase in the temperature of the system, we use the equation:
where,
q = Heat absorbed = 36.5 kJ = 36500J
m = Mass of water = 275 g
c = Specific heat capacity of water = 
= change in temperature = ? °C
Putting values in above equation, we get:
Hence, the temperature increase will be 31.70°C.
Answer:
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Explanation:
The question is:
<h2>What is the distance of the object from the mirror?</h2>
To answer this question, you must learn that, for plane mirrors, the distance of the object from the mirror is equal to the distance of the image formed behind the mirror.
For instance if you stand 1 meter away from a mirror (a plane one) the position of the image of you will be 1 meter behind the mirror.
Here, the initial distance between the image and the object is 40 cm. Then, the distance between the image and the miror is 20 cm, such as it is the distance between the object and the mirror.
That the distance of the object is reduced by 9.2 cm, must be understood as that the object was placed 9.2 cm closer to the mirror.
Then, the new distance of the object from the mirror is 20 cm - 9.2 cm = 10.8 cm. ← answer
The correct answer is "D".
Hope this helps!
