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Alborosie
3 years ago
14

Draw the structures of the starting materials needed to make 2-methylhept-3-yne in the spaces provided. The starting materials m

ay be any bromoalkane having five carbons or fewer.

Chemistry
1 answer:
DIA [1.3K]3 years ago
4 0

Answer: answered

Explanation:

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Which of the following is equal to Avogadro's number?​
saveliy_v [14]

Answer:

2.1.4.5 ang sagot jan charot lmg

5 0
3 years ago
Given the values of ΔGfo given below in kJ/mol, calculate the value of ΔGo in kJ for the combustion of 1 mole of butane to form
xz_007 [3.2K]

Answer:

Δ_rG=-2753kJ

Explanation:

Hello,

Butane's combustion is:

C_4H_{10}+\frac{13}{2} O_2-->4CO_2+5H_2O

Now the change in the Gibbs free energy for this reaction is computed via (don't forget that oxygen's Gibbs free energy of formation is 0 since it is an element):

Δ_rG=4Δ_fG_{CO_2}+5Δ_fG_{H_2O}-Δ_fG_{C_4H_{10}}

Δ_rG=4(-395kJ/mol)+5(-238kJ/mol)-(-17kJ/mol)

Δ_rG=-2753kJ/mol

Now, since the calculation is done for 1 mol of butane, the change in the Gibbs free energy for this fuel is:

Δ_rG=-2753kJ

Best regards.

4 0
3 years ago
A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the empirical formula
Mrrafil [7]

Answer:

PNCl_2

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2

Thus, the empirical formula is:

PNCl_2

Regards!

4 0
3 years ago
I need help plss asap
Basile [38]

Answer:

Volume = mass/density

Rearrange the equation for Mass:

Mass = Volume x Density

That is one way you can do it

Conceptually, just look at the units, the wood block's density is 0.6<u>g/cm^3</u> while the volume is 2.2 <u>cm^3</u>

So if density is every gram per centimeter cubed, and the volume is at centimeter cubed, the logical thing to do would be to multiply the density by the volume to get the total mass.

0.6g/cm^3   x   2.2cm^3 = 1.32g

<u>Therefore the mass of the block of wood is 1.32g </u>

8 0
2 years ago
Hydrogen and helium in the universe were formed by which of these phenomena?
baherus [9]
I think the answer is a
5 0
3 years ago
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