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elixir [45]
3 years ago
15

Can someone pls help me

Mathematics
2 answers:
baherus [9]3 years ago
8 0

Answer:

y=gx

3 = g X 1

g = 3/1

g = 3

6=3 X 2

9 = 3 X 3

g = 3

y = 3x

Paladinen [302]3 years ago
3 0

Answer:

y=3x

Step-by-step explanation:

In every collum, the x side increases by one but the y side increases by 3. which means it is multiplying.

0 x 3 = 0

1 x 3 = 3

2 x 3 = 6

3 x 3 = 9

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A PE teacher is charting the weight and BMI of her students. The table below shows the measured weight for all of her students f
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Answer:

122.67 average

Step-by-step explanation:

Mean = (every value added up)/(# of values)

Mean = (105 + 2(110) + 2(112) + 3(113) + 2(115) + 5(116) + 4(117) + 7(118) + 5(120) + 5(121) + 4(125) + 5(126) + 2(128) + 130 + 3(132) + 134 + 3(135) + 2(140) + 2(141) + 150)/60

= 7360/60

= 122.67

I had trouble understanding the data but I hope I did this right!

6 0
3 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
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The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

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3 0
2 years ago
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Answer:

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3 years ago
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7 0
3 years ago
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A hockey goalie got shot on 18 times . She saved 10 of the shots . Which ratio represents the amount of shots that went in to th
vredina [299]
<h3>Answer is   4:5</h3>

========================================================

Explanation:

She saved 10 shots out of 18 total, so that means 18-10 = 8 shots went in.

That forms the ratio 8:10 where we list the amount of shots that went in, followed by a colon, then the amount of shots that were saved. The order is important. From here, we divide both parts of the ratio by 2. The ratio 8:10 fully reduces to 4:5

Effectively, this means that for every 4 shots that went in, there were 5 shots that were blocked.

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3 years ago
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