Answer:
Given,
Mass, m = 2kg
Height or distance, s = 20m
Initial velocity, u = 0m/s
Acceleration due to gravity, g = 10m/s (It is 9.8m/s but can be assumed 10m/s for simplifying calculations)
(Because the object is is just dropped)
Final velocity, v = ?
Solution
v^2 = u^2 + 2as (u^2 means u raised to power 2)
=> v^2 = 0^2 + 2*10*20
=> v^2 = 400
=> v = 20
Thus the velocity just before the body strikes the ground will be 20m/s.
Answer:
1 cm3 is = 1 ml. Therefore 1000 g of seawater = 973.71 mL.
Explanation:
Seawater salinity will vary from place to place and with the temperature of the seawater. Of course the composition of dissolved substances in seawater, along with salt that is, will also vary from place to place.
On average, seawater in the world's oceans has a salinity of approximately 3.5%, or 35 parts per thousand. This means that for every 1 litre (1000 mL) of seawater, there are 35 grams of salts (mostly, but not entirely, sodium chloride) dissolved in it.
Seawater has an average density of 1.027 g/cm3, but this varies with temperature and salinity over a range of about 1.020 to 1.029.
A group of scientists claim that a new type of fuel will help reduce greenhouse gas emissions. to evaluate this claim you can a. calculate the price of producing the fuel. b. study the effect of a fuel spill on wetland ecosystems. c. determine the efficiency of the fuel in different types of engines. d. test the amount
