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katovenus [111]
3 years ago
12

How do I Solve x2 + 7x -20 = 0 using a quadratic formula?

Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

We first must determine the coefficients

a = 1

b = 7

c = -20

Then we use the quadratic formula:

x = [-7  +- sqr root (7^2 - 4 * 1  * -20)] / 2 * 1

x =  [-7 +- sqr root (129)] / 2

x1 = 4.3578166916 / 2

x1 = 2.1789083458

x2 = -18.3578166916  / 2

x2 = -9.1789083458

Step-by-step explanation:

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7 0
3 years ago
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Solve the following quadratic equation 6x2 – 7x = 20
siniylev [52]

Answer:

<h2>x = 5/2 , x = - 4/3</h2>

Step-by-step explanation:

6x² - 7x - 20 = 0

Using method of factorization

Rewrite - 7x as a difference

That's

6x² + 8x - 15x - 20 = 0

Factor the expression

That's

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Which is

(2x - 5) (3x + 4) = 0

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Divide both sides by 2

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Divide both sides by 3

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Hope this helps you

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=5x-8%3D4x-5" id="TexFormula1" title="5x-8=4x-5" alt="5x-8=4x-5" align="absmiddle" class="latex
Ilia_Sergeevich [38]

Answer:

Solution given:

5x-8=4x-5

or

5x-4x=8-5

x=3

<u>x</u><u>=</u><u>3</u>

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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