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maksim [4K]
3 years ago
14

Complete for 11 points.

Mathematics
2 answers:
-Dominant- [34]3 years ago
4 0
<h3>Logic Puzzle 1 The cars of Arnett, Bradley, Church and Dawson are gray, red, silver, and yellow. </h3><h3>1. Bradley and Church had lunch yesterday with the owner of the silver car. </h3><h3>2. Dawson saw the owners of the red car and the grey car passing his house yesterday.</h3><h3>3. The owner of the yellow car thinks he got a better deal on his car than Arnett and Dawson got on theirs. </h3><h3>4. Bradley's car is not a bright color. [bright colors are yellow and red.] Find each person's car color.</h3>

Answer: Arnett: red car; Bradley: grey car; Church: yellow car; Dawson: silver car.

(See attached image)

Step-by-step explanation:

■The yellow car isn't owned by Bradley (4)

■The yellow car isn't owned by Arnett (3)

■The yellow car isn't owned by Dawson (3)

►Then <em><u>Church owns the yellow car</u></em>.

■Dawson's car isn't red or gray (2)

►Then <em><u>Dawson owns the silver car</u></em>.

■Bradley's car isn't red (4)

►Then <em><u>Bradley owns the grey ca</u></em>r.

And so:

►<u><em>Arnett owns the red car</em></u>.

<h2><em>Spymore</em></h2>

Mrrafil [7]3 years ago
3 0

Answer:

Arnett - red car

Bradley - gray car

Church - yellow car

Dawson - silver car

Step-by-step explanation:

1st clue - we know that Bradley and Church can't have the silver car.

2nd clue - we know that Dawson can't have the red or gray car.

3rd clue - we know that Dawson and Arnett can't have the yellow car.

Based on the 2nd and 3rd clue, we know Dawson has the silver car because he can't have the red, gray, or yellow car.

4th clue - we know Bradley can't have the red or yellow car.

That leaves us with the gray car for Bradley because he had lunch with the owner of the silver car (which i consider also a bright color but i don't know if that counts).

so far:

dawson - silver car

bradley - gray car

and we know arnett can't have the yellow car because the owner of hte yellow car thinks he got a better car with his car then dawson and arnett, which leaves us with the red car for arnett.

dawson - silver car

bradley - gray car

arnett - red car

by process of elimination, that means church has the yellow car.

arnett - red car

bradley - gray car

church - yellow car

dawson - silver car

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A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, don’
cupoosta [38]

Answer:

The height of rectangle is 5 inches

Step-by-step explanation:

<u><em>The correct question is</em></u>

A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height

Let

x -----> the width of the rectangle in inches

y ----> the height of the rectangle in inches

d ---> diagonal measurement of the rectangle in inches

we know that

Applying the Pythagorean Theorem

d^2=x^{2}+y^{2}

we have

d=13\ in

so

13^2=x^{2}+y^{2}

169=x^{2}+y^{2} ----> equation A

x=y+7 ---> equation B

substitute equation B in equation A

169=(y+7)^{2}+y^{2}

solve for y

169=y^2+14y+49+y^{2}

2y^2+14y+49-169=0

2y^2+14y-120=0

solve the quadratic equation by graphing

using a graphing tool

The solution is y=5

see the attached figure

therefore

The height of rectangle is 5 inches

5 0
3 years ago
Look at the graph below and answer the following.
bearhunter [10]

Answer:

Part 1) The graph has three (3) x-intercepts and  has one (1) y-intercept

Part 2) The y-value of the minimum point is -3

Part 3) f(4)=3

Part 4) f(0)=3

Part 5) f(5)=1.5

Part 6) x=-6

Part 7) The horizontal line y=-1 intersects the graph three times

Part 8) The value of the function for f(6) is equal to zero

Part 9) The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) The function is positive on the interval (-3,6) and (10,11) and is negative on the interval (-6,-3) and (6,10)

Step-by-step explanation:

Part 1) Find the number of x-intercepts and y-intercepts of the graph

we know that

The<u> x-intercepts</u> are the values of x when the value of y (the function) is equal to zero

Look at the graph

The graph has 3 x-intercepts

The x-intercepts are the points (-3,0), (6,0) and (10,0)

The<u> y-intercepts</u> are the values of y when the value of x is equal to zero

Look at the graph            

The graph has 1 y-intercept

The y-intercept is the point (0,3)

Part 2) The y value of the minimum point on the graph is?

we know that

Look at the picture

The minimum point is (-6,-3)

therefore

The y-value of the minimum point is -3

Part 3)  f(4) is equal to?

we know that

f(4) is the value of the function when the value of x is equal to 4

Look at the graph

For x=4

The value of the function is equal to y=3

therefore

f(4)=3

Part 4) f(0) is equal to?

we know that

f(0) is the value of the function when the value of x is equal to 0

Look at the graph

For x=0

The value of the function is equal to y=3

therefore

f(0)=3

Part 5) f(5) is equal to?

we know that

f(5) is the value of the function when the value of x is equal to 5

Look at the graph

For x=5

The value of the function is about y=1.5  (see the attached figure)

therefore

f(5)=1.5

Part 6) The value of x when f(x)= -3 is?

Look at the graph

we have the point (-6,-3)

when the value of f(x)=-3

the value of x is equal to x=-6

Part 7) The horizontal line y = -1 intersects the graph _____ times?

Look at the graph

The horizontal line y=-1 intersects the graph three times (see the attached figure)

Part 8) f(6) is positive or negative?

Look at the graph

we have the point (6,0)

For x=6

The value of the function is equal to zero

Part 9) Is the graph increasing or decreasing on the interval -6?

Look at the graph

The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) Is the graph positive or negative on the interval 6

Look at the graph

The function is positive (f(x) > 0) on the interval (-3,6) and (10,11) and is negative (f(x) < 0) on the interval (-6,-3) and (6,10)

4 0
3 years ago
the length of a rectangle is 4 more than 3 times the width. If the perimeter of the rectangle is 18.4cm, what is the area of the
antoniya [11.8K]

Answer:

A = 10.27cm²

Step-by-step explanation:

Let's represent the width as x,

therefore since the length is 4 more than 3 times the width, it can be represent as 3x + 4,   Perimeter = 18.4cm

Perimeter of a rectangle = 2(L + B)

18.4= 2(3x+4+x)\\18.4= 6x+8+2x\\18.4-8=6x+2x\\10.4=8x\\x=\frac{10.4}{8}\\x=1.3

width = 1.3cm

Length = 3x + 4 = 3*1.3 + 4 = 7.9cm

Area of a rectangle = length x width

A = 7.9 * 1.3 = 10.27cm²

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3 years ago
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Step-by-step explanation:

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