Here is a link that should help you out
http://instituteforenergyresearch.org/topics/encyclopedia/fossil-fuels/
Most of the mass is located in the nucleus as suggested by Rutherford's gold foil experiment.
Answer:
the speed limit 6 seconds and the car will travel in 90m
Answer:
a) 
b) 
Explanation:
The frequency of the
harmonic of a vibrating string of length <em>L, </em>linear density
under a tension <em>T</em> is given by the formula:

a) So for the <em>fundamental mode</em> (n=1) we have, substituting our values:

b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since:

Answer:
The first
Explanation:
Cause it will continue in motion till another force is applied