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irina1246 [14]
2 years ago
7

The starship Enterprise approaches the planet Risa at a speed of 0.8c relative to the planet. On the way, it overtakes the inter

galactic freighter Astra. The relative speed of the two ships as measured by the navigator on the Enterprise is 0.5c. At what speed is Astra approaching the planet?
Physics
1 answer:
Alchen [17]2 years ago
8 0

Answer:

<em>0.3c</em>

<em></em>

Explanation:

The speed of Enterprise relative to Risa is 0.8c

Relative speed of both ships as measured from Enterprise is 0.5c

therefore, relative speed of Astra to Enterprise is 0.8c - 0.5c = <em>0.3c</em>

<em>this is also the relative speed with which Astra approaches the planet Risa since Enterprise's speed was calculated relative to Risa.</em>

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Bogdan [553]

It will take the battery 15 hours to discharge completely.

<h3>Energy stored in a battery</h3>

Energy is defined as the ability or capacity to work. The formula for calculating the energy stored in a battery is expressed as;

Energy stored=Power×Time

Energy stored = ΔV  * t  

where

ΔV is the change in velocity

t is the time

Substitute

Energy stored = 12.0 * 90.0

Energy stored = 1080 W.h

Total power consumed by the headlight = 2 * 36

Total power consumed by the headlight = 72Watts

Determine the time it takes to dischage

Time = Energy Stored/Power

Time = 1080/72

Time = 15hrs

Hence it will take the battery 15 hours to discharge completely.

Learn more on energy consumption here: brainly.com/question/24338873

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7 0
1 year ago
Please help me please help
Anna [14]

Answer:

2.12x 10 -3

Explanation:

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5 0
2 years ago
A(n) 636 kg elevator starts from rest. It moves upward for 4.5 s with a constant acceleration until it reaches its cruising spee
zmey [24]

Answer:

The average power delivered by the elevator motor during this period is 6.686 kW.

Explanation:

Given;

mass of the elevator, m = 636 kg

initial speed of the elevator, u = 0

time of motion, t = 4.5 s

final speed of the elevator, v = 2.05 m/s

The upward force of the elevator is calculated as;

F = m(a + g)

where;

m is mass of the elevator

a is the constant acceleration of the elevator

g is acceleration due to gravity = 9.8 m/s²

a = \frac{v-u}{t} \\\\a = \frac{2.05 -0}{4.5} \\\\a = 0.456 \ m/s^2

F = (636)(0.456 + 9.8)

F = (636)(10.256)

F = 6522.816 N

The average power delivered by the elevator is calculated as;

P_{avg} = \frac{1}{2} (Fv)\\\\P_{avg} = \frac{1}{2} (6522.816 \ \times \ 2.05)\\\\P_{avg} = 6685.89 \ W\\\\P_{avg} =  6.68589 \ kW\\\\P_{avg} =  6.686 \ k W

Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.

3 0
2 years ago
What volume In liters is a cube 20cm on a side? If the cube is filled with water what is the mass of the water?
frez [133]
1 liter = 1000 cm^3
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Since 1ml of water = 1 cm^3 = 1 grams
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7 0
2 years ago
Physical Science - 02.05 - Question #3
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Answer:

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