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koban [17]
3 years ago
11

If the acceleration of an object is zero at some instant in time, what can be said about its velocity at that time? 1. It is neg

ative. 2. It is positive. 3. It is not changing at that time. 4. Unable to determine. 5. It is zero.
Physics
1 answer:
Mkey [24]3 years ago
5 0

3. It is not changing at that time

Explanation:

If the acceleration of a body is zero at some instant in time, it implies that the velocity is not changing at that point in time. Velocity is the rate of change of displacement with time.

✓Acceleration and velocity shares a very close relationship.

✓ For a body to accelerate, the velocity must change. Acceleration is defined as the rate of change of velocity with time.

✓If at any point, a body moves with constant velocity i.e the velocity does not change with time, the acceleration becomes zero.

✓ For acceleration to occur, a body must change velocity.

Learn more:

Acceleration brainly.com/question/6323625

#learnwithBrainly

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The same number of protons. brainliest?(:
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A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
hammer [34]

Speed can be found through the application of concepts related to potential energy and kinetic energy, for which you have

KE = PE

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Re-arrange to find the velocity we have,

v^2 = 2gh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(0.54)}

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4 0
3 years ago
A 0.155 kg arrow is shot upward
Soloha48 [4]

Answer: 244.05 J

Explanation:

To find speed  at 30 m above the ground use equation:

V²=Vo²-2Gs

V0=31.4m/s

s=30m

G=9.81m/s²

-----------------------

V²=31.4²-2*9.81*30

V²=985.96+588.6

V²=1574.56

V=39.68m/s ---speed of arrow on 30 m obove the ground

Use equation for kinetic enrgy:

Ke=mV²/2

m=0.155kg

V=39.68m/s

-------------------------

Ke=0.155kg*(39.68m/s)²/2

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6 0
3 years ago
the magnitude of the electrical force acting between a +2.4x10-8c charge and 1+1.8x10-6 charge that are separated by 1.008m is
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Answer:

3.83×10¯⁴ N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +2.4x10¯⁸ C

Charge 2 (q₂) = +1.8x10¯⁶ C

Distance apart (r) = 1.008 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

The magnitude of the electrical force acting between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × 2.4x10¯⁸ × 1.8x10¯⁶ / (1.008)²

F = 0.0003888 / 1.016064

F = 3.83×10¯⁴ N

Thus the magnitude of the electrical force acting between the two charges is 3.83×10¯⁴ N

5 0
3 years ago
A 9­v battery is connected to a light bulb with a resistance of 3?. what is the current in the circuit
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