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3 years ago

Which of the following is contained in a pull start lawnmower?

Physics

2 answers:

Nonamiya [84]3 years ago

8 0

Answer:

The correct answer is a pulley and a wheel and axle.

Explanation:

Pull start lawnmowers usually have a traction mechanism designed to turn on the axle of the crankshaft and start the lawnmower engine. Also known as a recoil starter, the traction mechanism consists of a few different parts that work together to allow the user to start the mower engine.

The casing contains the pulley, starter cord, and rewind spring, all of which work together to form the mower's traction mechanism.

The wheels allow the machine to be moved on the ground.

Have a nice day!

Ksivusya [100]3 years ago

6 0

A wheel and axle and an inclined plane.

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A resistor with R=300 ? and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate a

qaws [65]

Answer:

impedance Z = 416.66 ohm

voltage across inducance V = 346.99 V

power factor = 0.720

Explanation:

given data

resistor R = 300

voltage amplitude = 500 V

resistor = 216 W

to find out

impedance and amplitude of the voltage and power factor

solution

we apply here average power formula that is

average power = I²×R ............1

I = $\frac{Vrms}{Z}$

average power = ( $\frac{Vrms}{Z}$ )²×R

Vrms = $\frac{1}{\sqrt{2} }$ × Vmax

Z = V × $\sqrt{\frac{R}{2P} }$

Z = 500 × $\sqrt{\frac{300}{2*216} }$

impedance Z = 416.66 ohm

and

we know voltage across inductor is here express as

V = I × X .............2

so here X will be by inductance

Z² = R² + (X)²

(X)² = 416.66² - 300²

X = 289.15 ohm

and I = $\frac{V}{Z}$

I = $\frac{500}{416.66}$

I = 1.20 A

so from equation 2

V = 1.20 × 289.15

voltage across inducance V = 346.99 V

and

average power = Vmax × Imax × cos∅

tan∅ = $\frac{289.15}{300}$

tan∅ = 43.95°

so power factor is

power factor = cos43.95°

power factor = 0.720

7 0

3 years ago

Sound Waves can be used to measure ocean depth. This done by sending a sound wave to the floor of the ocean and recording the ti

vazorg [7]

When the sound wave returns to the machine, you can measure
how long it took to return.

(You may notice that it's working just like RADAR, which does the
same thing with radio waves instead of sound waves.)

Even if you know how long the sound took to get to the bottom and
return to the top, you can't DO anything with this information if you
don't know the SPEED of the sound through the water. Not only
the inventory of this machine, but anyone who uses it, has to know
the speed of the sound through water in order to use the round-trip
time to calculate the depth.

3 0

4 years ago

5. Lady Gaga needed someone to buy more meat for her meat dress. The famous

krok68 [10]

Answer:

she can travel 24000 meters she cant reach the store she can get as much as 125 miles

Explanation:

7 0

3 years ago

A lawyer drives from her home, located 1 mile east and 8 miles north of the town courthouse, to her office, located 4 miles w

givi [52]

Answer:

d = 13 miles

Explanation:

Lets say the position of court house is origin in this case

her office is located at 4 miles west and 4 miles south of court house

so here we have coordinate of the office with respect to court house is given as

$r_1 = (-4\hat i - 4\hat j)$

now the position of her home is located at 1 miles east and 8 miles north of the court house

so the coordinates of her home is given as

$r_2 = (1\hat i + 8 \hat j)$

now the change in the position is given as the distance between office and home

$d = r_2 - r_1$

$d = 5 \hat i + 12 \hat j$

$d = \sqrt{5^2 + 12^2} = 13 miles$

4 0

4 years ago

What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?

Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

learn more about pressure:

brainly.com/question/22613963

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5 0

1 year ago