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vazorg [7]
3 years ago
13

What is the minimum amount of real solutions a quintic polynomial can have

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
1 this is the answer and I must have 20 characters
vodomira [7]3 years ago
3 0

Answer:

1

Step-by-step explanation:

I'm not sure if this is right, but I think it's 1. If you think about the simplest quintic polynomial, x^5, and set it to any real number, you'll always get 1 solution. I don't think it's possible to have 0 or no real solutions. Hope this helps!

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If a = 3 and b = 2, what is the value of the expression 11 + a - b ?
Vadim26 [7]
Substitute the values of a and b into the expression:
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4 0
3 years ago
I really need help with this one please
natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power \frac{3}{2} is on the variable we need to find so we multiply both the sides by an exponential power of \frac{2}{3} to be able to calculate 'a'.

P =  a^{\frac{3}{2} }, P^{\frac{2}{3} } = a^{\frac{3}{2}*\frac{2}{3}  },  P^{\frac{2}{3} } = a, 13.2^{\frac{2}{3} } = a = 5.58533 astronomical units.

Rounding it over to nearest hundredth we get 5.59 astronomical units.

6 0
3 years ago
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