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Anastaziya [24]
3 years ago
14

A large energy company produces electricity, natural gas, and oil. The production of a dollar's worth of

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

E = 64.05

NG = 52.29

O = 35.15

Step-by-step explanation:

With the statement we can create a system of 3X3 equations that would be as follows:

E = electricity

NG = natural gas

O = oil

0.35 * E + 0.15 * NG + 0.25 * O = 25

0.35 * E + 0.15 * NG + 0.2 * O = 15

0.1 * E + 0.1 * NG + 0.1 * O = 20

If we pass this system equations to matrix and subtract it from the identity matrix we would have the following:

0.65 * E - 0.15 * NG - 0.25 * O = 25

-0.35 * E + 0.85 * NG - 0.2 * O = 15

-0.1 * E - 0.1 * NG + 0.9 * O = 20

Solving this system of equations around here can be very long and impractical, therefore, I attach a photo of the process:

And the answer is:

E = 64.05

NG = 52.29

O = 35.15

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Answer:

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Step-by-step explanation:

This is honestly a pure guess, but I am guessing they want you to find a perfect triangle, and 3,4,5 is the smallest perfect triangle. Considering they also said it was a right triangle, I strongly beleive the answer is 5.

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A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
3 years ago
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