Empirical formula = mol ratio
mol H = 9.42 x 10²⁴ : 6.02 x 10²³ = 15.648
mol N = 3/9 x 15.648 = 5.216
mass N = 5.216 x 14 g/mol =73.024 g
Answer:
- Look up the specific heat capacity of AlF₃
- Calculate ΔT
- Calculate the mass of AlF₃
Explanation:
The formula for for the heat (q) absorbed by an object is
q = mCΔT, where
m = the mass of the sample
C = the specific heat capacity of the sample. and
ΔT = the change in temperature
1. What you must do
- Look up the specific heat capacity of AlF₃
- Calculate ΔT
- Calculate the mass of AlF₃
2. Sample calculation
For this example, I assume that the specific heat capacity of AlF₃ is 1.16 J·K⁻¹mol⁻¹
.
(a) Calculate ΔT

(b) Calculate m

Answer:
i cant see the image im good at chem if you can write it down in the comments ill answer it
Explanation:
Answer:
Use the Run as administrator shortcut menu option
Explanation: When working on an application in a computer system and you discovered that it requires more privileges than what is currently logged-on account, the best approach is to use the Run as an administrator shortcut menu option to handle or address this issue, using the Run as an administrator shortcut will give you unhindered access to the application which you intend to be logged on.