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icang [17]
3 years ago
15

PLEASE HELP ASAP

Chemistry
2 answers:
sashaice [31]3 years ago
3 0

Answer:

put a salt into the beakers

Airida [17]3 years ago
3 0
Mark Brainliest please

For ethanol you test a cereic ammonia nitrate test ethanol gives you blue voilet color so you can easily guess what is ethanol
for HCL you use a NACL which makes a compund neutral so you easily guess it
and rest of it LI2SO4 you can label it

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A 0.964 gram sample of a mixture of sodium formate and sodium chloride is analyzed by adding sulfuric acid. The equation for the
frosja888 [35]

Answer: 67.8 %.

Explanation:

Okay, let us delve right into the solution to the question;

The balanced chemical reaction is given by the equation (1) below;

2 HCOONa + H2SO4 ---------> 2 CO + 2 H2O + Na2SO4. ----------------------------------------------------------------------------(1).

From the balanced chemical reaction in equation (1) above we can see that; 2 moles of HCOONa reacts with one moles of tetraoxosulphate acid, H2SO4 to produce 2 moles of carbonmonoxide,CO; 2 moles of water, H2O and 1 mole of sodium tetraoxosulphate, Na2SO4.

The parameters given from the question are; total atmospheric pressure, P(t) = 752 torr, volume of CO= 242 mL = 0.242 Litres.

STEP ONE : find the carbon monoxide,CO pressure; P(CO).

Using the formula below;

P(t) = P(CO) + P(H2O). Hence;

P(CO) = P(t) - P(H2O). Note that P(H2O)= 19.8 torr.

==>P(CO)= 752 torr - 19.8 torr = 732.2 torr.

STEP TWO: calculate the number of moles of Carbonmonoxide,CO.

Using the formula below;

Number of moles= pressure(P) × volume(v) / gas constant(R) × temperature (T).

That is, n= PV/RT.

n= 732 torr × 0.242 Litres/ 62.4 × 295.15.

= 9.62 × 10^-3 mol of CO.

STEP THREE:

2 moles of HCOONa = 2 moles of CO.

=> 2 moles of HCOONa = 2 moles of CO/ 2 moles of CO = 1 mol( HCOONa/ CO).

Then, 9.62 × 10^-3 mol of CO × 1 mol( HCOONa/ CO).

==> 9.62 × 10^-3 mol HCOONa × molar masss of HCOONa(68 grams/mol)

= 0.654 grams.

Therefore, the percentage of sodium formate in the original mixture = 0.654 grams/ 0.964 gram × 100 = 67.8 %.

5 0
3 years ago
Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
wolverine [178]

Answer:

The correct answer is 2.75 grams of HCl.

Explanation:

The given balanced equation is:  

CaCO₃ (s) + 2HCl (aq) ⇒ CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Based on the given information, one mole of calcium carbonate is reacting with two moles of HCl. The molecular mass of HCl is 36.5 grams, thus, the mass of 2 moles of HCl will be, 36.5 × 2 = 73 grams

The molecular mass of CaCO₃ is 100 gram per mole, that is, the mass of 1 mole of CaCO₃ is 100 grams, therefore, the mass of HCl required for reacting with 3.75 grams of CaCO₃ will be,  

= 3.75 × 2 × 36.5 / 100 = 2.74 grams of HCl.  

8 0
3 years ago
Which statements describes Newton's law of universal gravitation ?
IrinaK [193]

Your answer is D. You're Welcome

8 0
3 years ago
Read 2 more answers
The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10-6 M/s.
avanturin [10]

Answer:

The rate would be lower and the concentration of reactants would be lower.

Explanation:

The rate of a chemical reaction depends on the rate constant and the concentration of reactants.

For Ex:

For a reaction experimentally given by A + B ----> C + D

Rate = k[A][B]

where k is the rate constant

          [A] = concentration of reactant A

          [B] = concentration of reactant B

As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.

Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.

8 0
3 years ago
Choose the correct products for the double replacement reaction below. Click here to access the solubility rules to determine wh
Lemur [1.5K]

MgCl₂ & PbSO₄ is the correct product for the given double replacement reaction.

<h3>What is double displacement reaction?</h3>

In the double displacement reaction displacement of two substrate will take place among two reactants and formation of products takes place.

In the question, PbCl₂ reacts with MgSO₄ and displacement between the cations takes place and formation of  MgCl₂ and insoluble precipitate PbSO₄ is formed.

Given reaction is represented as:

PbCl₂ + MgSO₄ → MgCl₂ + PbSO₄

According to the activity series, reactivity of Magnesium is more as compared to the lead atom. So lead is displaced by the magnesium atom and form the above given products.

Hence, option (3) is correct i.e. MgCl₂ & PbSO₄.

To know more about double displacement reaction, visit the below link:

brainly.com/question/26413416

8 0
2 years ago
Read 2 more answers
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