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just olya [345]
3 years ago
15

Which information in the periodic table indicates the number of protons in an atom?      A. the position of the element in its c

olumn              B. the element’s chemical symbol C.the element’s atomic mass D. the element’s atomic number
Chemistry
2 answers:
daser333 [38]3 years ago
5 0
HEYA!!!

The answer to your question is D.

Because atomic no. refers to no. of protons.

I hope it works out..

:)
Leni [432]3 years ago
3 0
Hi there!


D is true

the number of protons is same as atomic number in an atom


good luck!
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They differ in their molecular structures and properties.
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Difference in density between the two liquids
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What is the name of the aluminum ion? Al–1 Al+2 Al–3 Al+3
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Calculate the pH of a solution in which one normal adult dose of aspirin (640 mg ) is dissolved in 10 ounces of water. Express y
d1i1m1o1n [39]

The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Given data :

mass of aspirin = 640 mg = 0.640 g

volume of water = 10 ounces = 0.295735 L

molar mass of aspirin = 180.16 g/mol

moles of aspirin = mass / molar mass = 0.00355 mol

<h3>Determine the pH of the solution </h3>

First step : <u>calculate the concentration of aspirin</u>

= moles of Aspirin / volume of water

= 0.00355 / 0.295735

= 0.012 M

Given that pKa of Aspirin = 3.5

pKa = -logKa

therefore ; Ka = 10^{-3.5} = 3.162 * 10^{-4}

From the Ice table

3.162 * 10^{-4} = \frac{x + H^+}{[aspirin]}  = \frac{x^{2} }{0.012-x}

given that the value of Ka is small we will ignore -x

x² = 3.162 * 10^{-4} * 0.012

x = 1.948 * 10^{-3}  

Therefore

[ H⁺ ] = 1.948 * 10^{-3}

given that

pH = - Log [ H⁺ ]

     = - ( -3 + log 1.948 )

     = 2.71 ≈ 2.7

Hence we can conclude that The pH of the solution in which one normal adult dose aspirin is dissolved is :  2.7

Learn more about Aspirin : brainly.com/question/2070753

4 0
1 year ago
How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?
kati45 [8]

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

hence 0.85X0.448

3 0
3 years ago
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