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just olya [345]
3 years ago
15

Which information in the periodic table indicates the number of protons in an atom?      A. the position of the element in its c

olumn              B. the element’s chemical symbol C.the element’s atomic mass D. the element’s atomic number
Chemistry
2 answers:
daser333 [38]3 years ago
5 0
HEYA!!!

The answer to your question is D.

Because atomic no. refers to no. of protons.

I hope it works out..

:)
Leni [432]3 years ago
3 0
Hi there!


D is true

the number of protons is same as atomic number in an atom


good luck!
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If the mass is 6.5g, and the volume is 25mL.. what is the density? PLEASE ANSWER ASAP
julia-pushkina [17]

Answer:

p = 260 kilogram/cubic meter

Explanation:

ρ =  \frac{m}{V} \\

  = \frac{6.5 g}{25mL}

=  0.26 gram/milliliter

=  260 kilogram/cubic meter

7 0
3 years ago
Which statements about fresh-water sources are true.? (Multiple Choice) (please help asap thanks!:)
Kay [80]

Answer:

The correct answers are:
"Only about 3 percent of Earth's water is fresh water."

"About 75% percent of the fresh water on Earth is frozen in ice sheets."

"The largest source of usable fresh water is groundwater."

Explanation:

3 percent of Earth's water is most certainly fresh water. Confirmed with a few fact checks.

The largest source of usable fresh water on Earth is groundwater. It's more difficult to access but it's there and much more usable than water say frozen in ice on the sea.

The most correct option left would be 75% of Earth's freshwater being in ice sheets even though it's about 70%.

3 0
2 years ago
Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O
Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

K_{sp} = 5.02\times 10^{-6}

First we have to calculate the solubility of OH^- ion.

The balanced equilibrium reaction will be:

Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-

Let the solubility will be, 's'.

The concentration of Ca^{2+} ion = s

The concentration of OH^- ion = 2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][OH^-]^2

Let the solubility will be, 's'

K_{sp}=(s)\times (2s)^2

K_{sp}=(4s)^3

Now put the value of K_[sp} in this expression, we get the solubility.

5.02\times 10^{-6}=(4s)^3

s=1.079\times 10^{-2}M

The concentration of Ca^{2+} ion = s = 1.079\times 10^{-2}M

The concentration of OH^- ion = 2s = 2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M

First we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (2.158\times 10^{-2})

pOH=1.67

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33

Therefore, the pH of a saturated solution is, 12.33

7 0
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dedylja [7]

Answer:

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Answer:

Explanation:

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