Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
<span>2x + 5 = 27
subtract 5 to both sides
2x + 5 - 5 = 27 - 5
simplify
2x = 22
divide both sides by 2
2x/2 = 22/2
simplify
x = 11
answer is </span><span>11 (second choice)
</span>
hope that helps
The solution to x + 8.5 = 64.5 is 56.
x + 8.5 = 64.5
- 8.5 - 8.5
---------------------------
x = 56