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BigorU [14]
3 years ago
15

Please help me in this question.

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

Step-by-step explanation:

(i) Area of ABCD = (base1+base2)*height/2

                           = (6+12)*4/2 = 36 cm2

(ii) Volume = Area of ABCD * length = 36 * 25 = 900 cm3

(iii) Total SA = Area of ABCD *2 + 25*5*2 + 6*25 + 12*25

                    = 72                         + 250      + 150   + 300

                    = 772cm2

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3 years ago
Listed below are prices in dollars for one night at different hotels in a certain region. Find the​ range, variance, and standar
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Answer:

Range = $115

Variance = $1915.2857

Standard deviation = $43.764

Step-by-step explanation:

Given the data:

234 160 119 131 218 207 146 141

Arranging in ascending order :

119, 131, 141, 146, 160, 207, 218, 234

The range = maximum - minimum

The range = 234 - 119 = 115

The variance :

Σ(x - mean)²/n-1

The mean = Σx / n

The mean = 1356 / 8 = 169.5

Variance :

Σ(x - mean)² = (119-169.5)² + (131-169.5)² + (141-169.5)² + (146-169.5)² + (160-169.5)² + (207-169.5)² + (218-169.5)² + (234-169.5)² = 13407

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Variance = 13407 / 7 = 1915.2857

Standard deviation = √variance

Standard deviation = √1915.2857

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8 0
3 years ago
After you complete your survey of students reported heights at your school, you discover that your sample is biased. Exactly 10%
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What we can say with a good deal of certainty is that our sample is biased towards the higher spectrum and that the real value of the mean for our population is lower than the obtained value of our sample. If this is true, we should expect for the standard deviation to be higher than in the population. 
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A) what is average rate of change of f(x) over the interval from x=5 to x=9? (table shows values of f(x). graph shows function o
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Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

The average rate of change of a function over the interval [a,b] is equal to \frac{f(b)-f(a)}{b-a}, hence:

\frac{f(b)-f(a)}{b-a}\\\\\frac{f(9)-f(5)}{9-5}\\\\\frac{14-(-4)}{9-5}\\ \\\frac{14+4}{4}\\ \\\frac{18}{4}\\ \\\frac{9}{2}

Therefore, the average rate of change of f(x) over the interval [5,9] is \frac{9}{2}.

<u>Part B</u>

Do the same thing as in Part A:

\frac{f(b)-f(a)}{b-a}\\ \\\frac{f(1)-f(0.25)}{1-0.25}\\ \\\frac{2-5}{0.75}\\ \\\frac{-3}{0.75}\\ \\-4

Therefore, the average rate of change of g(x) over the interval [0.25,1] is -4.

<u>Part C</u>

To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).

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2 years ago
Mrs. Hartill drove 3.1 miles to the grocery store, then 4.25 miles to the salon, and 10.8 miles to her sons house. How many mile
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Answer: 18.15 miles

Step-by-step explanation:

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