Answer: 46x3
I hope this helped! :)
Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
Answer:
D
Step-by-step explanation:
-2 | -8
-1 | -24
0 | -10
1 | 2
2 | 3
Graph D:
point 1. -2 , -8
point 2. -1 , -24
point 3. 0 , -10
point 4. 1 , 2
point 5. 2 , 3
1 gallon is 4 quarts or 8 pints. 9 gallons - 3 gallons= 6 gallons
Then convert it to quarts so, 6×4=24 quarts.
Then subtract that by 10 quarts so, 24-10=14 quarts.
Because you requested the number in pints, you have to convert it again and because there are 2 pints in a quart you multiply it by 2 so, 14×2=28 pints left over.
The first thing you do is cross multiply which is 3/4x=48 (3/4 = 0.75). Therfore you divide each side by .75. The left side cancels out. For the right side you divide 48 by .75 and gives you 64. x=64
