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FrozenT [24]
3 years ago
11

What is the quotient of(x^3+3x^2-4x-12

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:MATHPAPA.COM

Step-by-step explanation:

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Type the slope-intercept equation
Zolol [24]

Answer: y=x-2

Step-by-step explanation:

P=(x1,y1), and Q=(x2,y2), we use this to find m because m=y2-y1/x2-x1, by using this you'll see that the slope equals one. So now we have our slope. To solve for b, you need to do b=y1-m*x1, or b=y2-m^x2, it doesn't matter which one you do because the results will be the same, but it is good to check over it. Now that you have your slope and y-intercept, you can put it into the equation y=mx+b, so the answer to the problem is y=x-2.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)

- Cutiepatutie ☺❀❤

3 0
3 years ago
F(x)=( x^4 + 5x^3 - 2x^2 + 5x - 3) d(x)=( x^2 + 1) Divide f(x) by d(x)
VLD [36.1K]
<span>f '(x) = [(-40x +11)(7x - 9) - 7(-4x +3)(5x + 1)]/(7x - 9)2</span> 
<span>= [(-280x2<span> + 360x + 77x - 99) - 7(-20x</span>2<span> - 4x + 15x + 3)]/(7x - 9)</span>2</span> 
<span>= [(-280x2<span> + 437x - 99) + (140x</span>2<span> + 28x - 105x - 21)]/(7x - 9)</span>2</span> 
<span>= (-140x2<span> +360x - 120)/(7x - 9)</span><span>2
</span></span>
i think thats how you would solve it
hope this helps tho:)
4 0
3 years ago
Suppose the parent population has an exponential distribution with a mean of 15 and standard deviation of 12. Use the Central Li
bazaltina [42]

Answer:

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the population, we have that:

Mean = 15

Standard deviaiton = 12

Sample of 30

By the Central Limit Theorem

Mean 15

Standard deviation s = \frac{12}{\sqrt{30}} = 2.19

Approximately normal

The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.

4 0
3 years ago
What are the values of each variable
Ksenya-84 [330]

Answer:

Step-by-step explanation:

3 0
3 years ago
What is the value of d + e + f when d = 20, e = –4 and f = –2?
saw5 [17]
20 - 4 - 2 = 14.  A negative number is just like subtracting it.
5 0
3 years ago
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