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FrozenT [24]
3 years ago
11

What is the quotient of(x^3+3x^2-4x-12

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:MATHPAPA.COM

Step-by-step explanation:

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If h(x) = -5x -10 find (h-2)
gizmo_the_mogwai [7]
H(x) = -5x - 10
h(-2) = -5(-2) - 10
h(-2) = 10 - 10
h(-2) = 0
8 0
3 years ago
A rectangular gasoline tank can hold 45.0 kg of gasoline when full. what is the depth of the tank if it is 0.450 m wide by 0.900
garri49 [273]
The answer is 0.154 m

Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒   V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³

Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625  / 0.405
d = 0.154 m
7 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
In 1940​, a certain​ country's population was 79,042,573 and its area was 2,919,166 square miles. In 2000​, the​ country's popul
Debora [2.8K]

Answer:

Step-by-step explanation:

3 0
3 years ago
50 POINTS! I MARK BRAINLEST AND SAY THANKS!
Phantasy [73]
Y *x =20

y +x =9

rewrite 1st eq. as y = 20/x

subsituute that into 2nd eq.

20/x +x =9

multiply each term by X

20 +x^2 = 9x
 subtract 9x from each side:

x^2 - 9x +20 = 0

now factor:

(x-5) (x-4) = 0

solve for x
5-5 = 0
 4-4 = 0

so X can be 4 or 5

replace x into equations and solve for Y

 so when X = 4, Y = 5
 When X = 5, Y = 4

x= 5,4
y = 4,5



5 0
3 years ago
Read 2 more answers
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